php - 这段 PHP/Mysql 代码哪里出了问题？

Question

以下代码仅适用于第一个值 (puzzle_level==4)，它应该做的是打印出 puzzle_level==4, 5, 6 & 7 :(

    $result = mysql_query("
    SELECT puzzle_level, max(final_score) as highest_final_score
        FROM sleuth_game
        WHERE playerID='$_SESSION[customerID]' and final_score > 1
        GROUP BY puzzle_level
        ORDER BY puzzle_level");  //Load in a the highest scores
    while($row = mysql_fetch_array($result)) {
        echo "<p>".$row['highest_final_score']."</p>";
    }

编辑: 在数据库中，所有游戏都是 puzzle_level 4、5、6 或 7。我希望的输出是玩家在每个 puzzle_level 中获得的最高分数，但我编写的代码仅显示 puzzle_level==4 的最高分数.

Answer 1

您到底希望在 SQL 查询的 WHERE 语句中使用“final_score>1”实现什么目的？

SELECT puzzle_level, max(final_score) as highest_final_score
FROM sleuth_game
WHERE playerID='$_SESSION[customerID]' and final_score > 1
GROUP BY puzzle_level
ORDER BY puzzle_level

也许 HAVING 子句是您想要实现的目标的解决方案:

SELECT puzzle_level,MAX(final_score) AS highest_final_score
FROM sleuth_game
WHERE playerID='$_SESSION[customerID]'
GROUP BY puzzle_level
HAVING MAX(final_score)>1
ORDER BY puzzle_level