mysql - 从2个表中获取数据(MySQL)

Question

我有两个具有相同列的表，我需要显示两个表中的所有列，但现在我得到了每行中的所有列，例如。每行定位器 2 次，它必须仅显示正确表中的 1 个。

SELECT a.*, b.* FROM  clothes a, items b group by a.locator,b.locator

我该怎么做？

我将从两个带有行的表中输出它。 “名称”、“定位器”、“价格”和 WHERE“ibutik”= 1。

带有测试行的衣服表:

   CREATE TABLE IF NOT EXISTS `clothes` (
   `id` int(11) NOT NULL AUTO_INCREMENT,
   `locator` varchar(48) DEFAULT NULL,
   `name` varchar(32) DEFAULT NULL,
     `price` int(11) DEFAULT '100',
    `level` smallint(6) DEFAULT '0',
     `type` smallint(6) DEFAULT NULL,
     `sex` smallint(4) DEFAULT NULL,
     `x_offset` smallint(6) DEFAULT '0',
     `y_offset` smallint(6) DEFAULT '0',
     `nontradeable` tinyint(4) DEFAULT '0',
     `ibutik` int(1) NOT NULL,
     `koebt` int(9) NOT NULL,
     PRIMARY KEY (`id`)
   ) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=55 ;


 INSERT INTO `clothes` (`id`, `locator`, `name`, `price`, `level`, `type`, `sex`, `x_offset`, `y_offset`, `nontradeable`, `ibutik`, `koebt`) VALUES
   (1, '1.png', 'Male body', 100, 1, 2, 1, 0, 0, 0, 0, 0),
   (3, '1.png', 'Female body\r\n', 100, 1, 1, 2, 0, 0, 0, 0, 0))

和项目:

CREATE TABLE IF NOT EXISTS `items` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
  `locator` varchar(32) DEFAULT '',
  `name` varchar(32) DEFAULT '',
  `price` int(11) DEFAULT '100',
  `level` smallint(6) DEFAULT '0',
  `rotateable` tinyint(4) DEFAULT '0',
  `x_offset` smallint(6) DEFAULT '0',
  `y_offset` smallint(6) DEFAULT '0',
  `z_index` smallint(6) DEFAULT '0',
  `nontradeable` tinyint(4) DEFAULT '0',
  `ibutik` int(1) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=20 ;



INSERT INTO `items` (`id`, `locator`, `name`, `price`, `level`, `rotateable`, `x_offset`, `y_offset`, `z_index`, `nontradeable`, `ibutik`) VALUES
(1, 'rodplante.png', 'Rød plante', 10, 0, 0, 0, 0, 0, 0, 1),
(2, '1.png', 'Gul plante', 0, 0, 0, 0, 0, 0, 0, 0),
(3, '2.png', 'Gul plante', 0, 0, 0, 0, 0, 0, 0, 0),

Answer 1

可以尝试这样的事情:

select id,locator,name,price, tableName from 
(
  select a.id as id, a.locator as locator, a.name as name, 
     a.price as price, a.ibutik as ibutik, 'closes' as tableName 
    from  clothes a
  union all
  select b.id,b.locator,b.name,b.price,b.ibutik,'items' from items b 
) foo
where ibutik=0;

已通过 sqlFiddle 进行验证.