我创建了新的触发器，它必须更新员工的工资。它从表付款中获取 2 个值(现金和月数)，并将它们分为“how_much_to_pay”列。
我看了主题: MySQL triggers cannot update rows in same table the trigger is assigned to. Suggested workaround?
但这对我没有帮助，因为他们只使用一张表，并且可以毫无问题地放置"new"。
这是我的触发器:
create trigger pay_out before insert on `payment_out`
for each row
then
UPDATE `payment_out` o
INNER JOIN payment p ON p.id_1 = o.id_1 AND o.id2 = p.id2
SET o.`how_much_to_pay` = p.cash / p.months;
end;
$$
以下是表格:
table payment_out
id1
id2
how_much_to_pay
table payment
id1
id2
cash
months
以及错误本身:
1442 - Can't update table payment_out in stored function/trigger because it is already used by statement which invoked this stored function/trigger.
最佳答案
如果两个表之间有一对一的关系，那么您可以在 BEFORE INSERT 触发器中使用此代码 -
BEGIN
SELECT p.cash, p.months INTO @cash, @months
FROM payment p
WHERE p.id_1 = NEW.id_1 AND p.id2 = NEW.id2;
SET NEW.how_much_to_pay = @cash / @months;
END
关于mysql - 无法更新触发器中的表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13696960/