MySQL 和推送查询数组在一起

Question

我这里有这段代码

$sql_array = array();
if($result['user_id'] == 'OA'){
                $sql = "select distinct id, FirstName, LastName from table_one ti left join table_two sp on (sp.user_id = ti.id) or (sp.user_id = ti.id)";
                $query = $this->db->query($sql);
                $results_array = $query->result_array();
                $sql_array = array_push($sql_array, $results_array);
            }
            elseif($result['user_id'] == 'SH'){
                $sql = "select distinct id, first_name, last_name from table_three teo left join table_two sp on sp.user_id = teo.id";
                $query = $this->db->query($sql);
                $results_array = $query->result_array();
                $sql_array = array_push($sql_array, $results_array);
            }elseif($result['user_id'] == 'OF'){
                $sql = "select distinct id, first_name, last_name from table_four os left join table_two sp on sp.user_id = os.id";
                $query = $this->db->query($sql);
                $results_array = $query->result_array();
                $sql_array = array_push($sql_array, $results_array);
            }elseif($result['user_id'] == 'US'){
                $sql = "select distinct ID, substring_index(display_name, ' ', 1) as 'FirstName', substring_index(display_name, ' ', -1) as 'LastName' from table_five tu left join table_two sp on sp.user_id = tu.id";
                $query = $this->db->query($sql);
                $results_array = $query->result_array();
                $sql_array = array_push($sql_array, $results_array);
            }

它会遍历所有的 $result['user_id'] 并查看基于 $result['user_id'] 运行哪个查询字符串......使用上面的代码我得到一个错误 array_push () 期望参数 1 为数组，给定整数

我做错了什么或者有更好的方法吗？

谢谢， J

Answer 1

为什么不使用 [] 语法？

if($result['user_id'] == 'OA'){
            $sql = "select distinct id, FirstName, LastName from table_one ti left join table_two sp on (sp.user_id = ti.id) or (sp.user_id = ti.id)";
            $query = $this->db->query($sql);
            $results_array = $query->result_array();
            $sql_array[] = $results_array;
        }

关于错误的原因是因为您影响了 array_push 返回到数组变量。问题是 array_push 返回一个整数，因此在循环的第二轮您将尝试传递一个整数作为 array_push 的第一个参数