java - 从mysql数据库获取数据并显示在android上

Question

我必须开发一个 Android 示例。

它执行从 mysql 数据库获取数据并显示在 Android 应用程序上。

我使用了以下网络服务代码:

public class EditProfile {
public String customerData(String Username,String Password,String Firstname,String Lastname,String Company,String Taxnumber,String Baddress,String Bcity,String Bstate,String Bcountry,String Bzipcode,String Saddress,String Scity,String Sstate,String Scountry,String Szipcode,String Email,String Phone,String Fax,String Url){

 String customerInfo = "";

try{

Class.forName("com.mysql.jdbc.Driver");
Connection con = DriverManager.getConnection("jdbc:mysql://10.0.0.75:3306/xcart432pro","root","");
 PreparedStatement statement =  con.prepareStatement("SELECT * FROM xcart_customers where login = '"+Username+"'");
 ResultSet result = statement.executeQuery();

while(result.next()){
            customerInfo = customerInfo + result.getString("login") + ":" +result.getString("password")+ ":" +result.getString("firstname")
    }

     }
     catch(Exception exc){
         System.out.println(exc.getMessage());
           }
        return customerInfo;
        }

我使用了下面的android代码:

 public class RetailerActivity extends Activity {
    private final String NAMESPACE = "http://xcart.com";
  private final String URL = "http://10.0.0.75:8085/XcartLogin/services/EditProfile?wsdl";
  private int i;
  private final String SOAP_ACTION = "http://xcart.com/customerData";
  private final String METHOD_NAME = "customerData";

  String str,mTitle;
  /** Called when the activity is first created. */
  @Override
    public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
         try {
        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); 
     SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);

     envelope.setOutputSoapObject(request);

     HttpTransportSE ht = new HttpTransportSE(URL);

       ht.call(SOAP_ACTION, envelope);

         SoapPrimitive s = response;
        str = s.toString();
       String[] words = str.split(":");
       TextView tv = (TextView) findViewById(R.id.user);
        tv.setText(Username);

      EditText tv1 = (EditText) findViewById(R.id.pass);


        tv1.setText(words[1].toString());
      EditText tv2 = (EditText) findViewById(R.id.tf_userName);


         tv2.setText(words[2].toString());

          for (int i = 0, l = words.length; i < l; ++i) {
                }}

       catch (Exception e) {
          e.printStackTrace();
           }
            }}

这里我必须运行应用程序，意味着从mysql数据库获取数据并在android上显示数据。但是我没有得到响应。我怎样才能得到它。

这里我必须写出静态条件:

SELECT * FROM xcart_customers where login = 'mercy'"); means fetching the data from mysql database and display the data for that user.its successfully worked.

但是我已经动态地编写了代码意味着

"SELECT * FROM xcart_customers where login = '"+Username+"'"); means

没有收到回复。请帮助我。

我如何开发这些。给我解决方案或想法。

Answer 1

可能是用户名变量不包含有效值，请尝试在调用查询之前打印它，也就是说，我看到您正在使用PreparedStatement，当使用PreparedStatement时，您应该使用来自 PreparedStatement API 的方法以及查询中的占位符。

 PreparedStatement statement =  con.prepareStatement("SELECT * FROM xcart_customers where login = ?);
statement.setString(1, username);
 ResultSet result = statement.executeQuery();