我有一个这样的查询:
select files_id, count(DISTINCT shared_user_id) FROM fileupload_share GROUP BY files_id;
我想在 Django 查询中进行转换。尝试过这样的:
count = Share.objects.filter(users_id=request.user.id).values_list('shared_user_id').distinct().count()
但没有给我按所需输出进行分组。我希望输出以列表形式返回
count = [1, 2, 3, 1]
模型.py:
class Share(models.Model):
users = models.ForeignKey(User)
files = models.ForeignKey(File)
shared_user_id = models.IntegerField()
shared_date = models.TextField()
class File(models.Model):
users = models.ForeignKey(User)
file_name = models.CharField(max_length=100)
type = models.CharField(max_length=10)
source = models.CharField(max_length=100)
start_date = models.TextField()
time_overview = models.CharField(max_length=55)
end_date = models.TextField()
duration = models.TextField()
size_overview = models.IntegerField()
size = models.TextField()
flag = models.TextField()
flag_r = models.TextField()
我怎样才能做到这一点?谢谢
最佳答案
尝试这样的事情:
files = File.objects.filter(users_id=request.user.id).annotate(count=Count('share__shared_user_id')
那么你应该有
for f in files:
print f.file_name, f.count
关于mysql - 如何将此 MySQL 查询转换为 Django 查询?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15432049/