我有两个表,它们是连接在一起的,每个表的 ID 和下面的元素都是相似的。
parentID | objectName | subID ID| className| subName |
_____________________________ ________________________
84 | Test | 14 14| BOM | Test
84 | More | 16 14| PDF | Test
84 | Sub | 15 15| Schematics | Test2
我想列出相关元素的类别名称和子ID。几个ObjectNames将有几个相关的类。
PHP 代码:
$objects = mysqli_query($con,"SELECT * from subobject");
$join = mysqli_query($con, "SELECT * FROM subrelation AS subrelation INNER JOIN subobject AS subobject ON subobject.subId = subrelation.ID;");
echo "<ul>";
while($obj = mysqli_fetch_array($objects) and $row = mysqli_fetch_array($join))
{
echo "<li>". $obj['objectName'];
echo "<ul>";
//ITERATION GOES HERE
if($obj['objectName'] == $row['subName'])
echo "<li>". "$row[className]" . "</li>";
//END OF ITTERATION
echo "</ul>";
echo "</li>";
}
echo "</ul>";
?>
和输出列表:
-Test
-BOM
-Sub
-Schematics
-More
每个字段下应该有更多列出的值。
最佳答案
看来您需要稍微简化一下代码。我的猜测是,您出现问题是因为每个结果集中的行数不同。这使得您的 while
循环在完成较小结果集(可能是 $objects
)的处理后退出,即使较大集合中还有更多元素。
一种解决方案是对查询结果进行排序,在 while
循环中仅使用一个条件,并跟踪您当前正在使用哪个 objectName
字符串$curr_objectName
:
$join = mysqli_query($con, 'SELECT * FROM subrelation AS subrelation INNER JOIN subobject AS subobject ON subobject.subId = subrelation.ID ORDER BY subobject.objectName;');
$curr_objectName = '';
echo '<ul>';
while($row = mysqli_fetch_array($join)) {
$subName = $row['subName'];
if($subName != $curr_objectName)) {
if($curr_objectName != '') {
#close the previous list
#will be skipped on the first loop iteration
echo '</ul>';
echo '</li>';
}
#start a new list
$curr_objectName = $subName;
echo '<li>'. $obj['objectName'];
echo '<ul>';
} else {
echo '<li>'. $row['className'] . '</li>';
}
}
echo '</ul>';
关于php - 迭代表中的列表值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16740016/