PHP 数组向后输出

Question

这是我当前的 preg_match_all 输出

Array
(
[0] => Array
    (
        [0] => 2 Sentence text here
    )

)

Array
(
[0] => Array
    (
        [0] => 3 Sentence text here.
        [1] => 4 Sentence text here.
        [2] => 5 Sentence text here.
    )

)

我试图将每个输出作为新行插入表中，但它认为每个 [0] [1] [2] 都是一个新列。如何将数组插入mysql？

$query = "INSERT INTO table (col1) VALUES ";
foreach ($matches as $item) {
$query .= "('".$item[0]."'),";
}
$query = rtrim($query,",");
$result = mysql_query($query);

上面显然只插入数组的第一行

Answer 1

好吧，你在另一个数组中有一个数组，所以......

$query = "INSERT INTO table (col1) VALUES ";

if(!empty($matches))
{
    foreach ($matches as $item) {
        foreach ($item[0] as $items) {
            $query .= "('".$items."'),";
        }
    }
}

<小时/>

if(!empty($matches))
{
    foreach ($matches[0] as $item) {
        $query .= "('".$item."'),";
    }
}

取决于您如何获得数组匹配。

<小时/>

$query = rtrim($query,",");
$result = mysql_query($query);

这样你就会得到这个查询:

INSERT INTO table (col1) VALUES ('2 Sentence text here'), ('3 Sentence text here'), ('4 Sentence text here'), ('5 Sentence text here')

这是使用单个 INSERT 语句在一列中插入多个值的有效方法。

注意: Please, don't use mysql_* functions in new code 。它们不再维护and are officially deprecated 。请参阅red box ？了解 prepared statements相反，并使用 PDO ，或MySQLi -this article将帮助您决定哪个。如果您选择 PDO，here is a good tutorial .