mysql - 无法弄清楚为什么每个查询都返回 else (情况时)

Question

我正在 PHP 变量中编写此代码，其中 $username 和 $email 被替换。我在屏幕上回显了这一点，看起来是正确的。我假设 MySQL 代码存在问题，因为我总是得到的唯一结果是“可接受”。有什么帮助吗？

SELECT CASE 
WHEN email='$email' THEN '$email is already associated with an account' 
WHEN username='$username' THEN '$username is already taken' 
ELSE 'acceptable' 
END AS result FROM collaborator 
UNION 
SELECT CASE 
WHEN email='$email' THEN '$email is already associated with an account' 
WHEN username='$username' THEN '$username is already taken' 
ELSE 'acceptable' 
END AS result 
FROM waitForValidation 
LIMIT 1;

Answer 1

您的问题是在一个或另一个表中无法匹配，因此 'acceptable' 来自某处。然后，您使用union，它通常通过排序来删除重复项。尝试以不同的方式进行匹配:

select (case when max(email) = $email then '$email is already associated with an account' 
             when max(username)='$username' THEN '$username is already taken'
             else 'acceptable'
        end)
from (select email, username
      from collaborator
      where email = '$email' or username= '$username'
      union
      select email, username
      from waitForValidation 
      where email = '$email' or username= '$username'
     ) t

这使用 max() 而不是 limit 来处理没有匹配项的情况。在这种情况下，max() 将返回 NULL，因此前两个条件将失败。