java - 选择值时 hibernate 出错

标签 java mysql hibernate servlets

当我尝试向 mysql 搜索值时出现错误

这是 servlet

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    // Obtención de la sesión con Hibernate 4.x
    Configuration configuration = new Configuration().configure();
    ServiceRegistry serviceRegistry = new ServiceRegistryBuilder().applySettings(configuration.getProperties())
    .buildServiceRegistry();
    SessionFactory sessionFactory = configuration.buildSessionFactory(serviceRegistry);
    Session session = sessionFactory.openSession();


    BuscaCorreo(session);


}


private static void BuscaCorreo(Session session) {

    int id =  1;


LoginDAO loginDAO = new LoginDAO(session);  
Login login =  new Login();
    login.setId(id);
    loginDAO.find(login);

    System.out.println(login.getCorreo());
    }

这是拥有所有 get 和 set 时的 Login 类

@Entity

公共(public)类登录实现可序列化{ 私有(private)静态最终长serialVersionUID = 7698531046982304548L;

@Id
private long id;
private String correo;
private String clave;



public Login(){


}


public Login(long id, String correo, String clave) {
    super();
    this.id = id;
    this.correo = correo;
    this.clave = clave;
}




public String getCorreo() {
    return correo;
}



public void setCorreo(String correo) {
    this.correo = correo;
}



public String getClave() {
    return clave;
}



public void setClave(String clave) {
    this.clave = clave;
}


public long getId() {
    return id;
}


public void setId(long id) {
    this.id = id;
}

这是连接到 mysql 时的 LoginDAO 类

    private Session session;

public LoginDAO(Session session) {
    this.session = session;

}



public String find(Login id) {
    String login = null;
    try {
    login = (String) session.load(Login.class, id);
    } catch (Exception e) {
    e.printStackTrace();
    }
    return login;
    }

当我运行应用程序时出现此错误

log4j:WARN No appenders could be found for logger (org.jboss.logging).
log4j:WARN Please initialize the log4j system properly.
org.hibernate.TypeMismatchException: Provided id of the wrong type for class com.utp.soft6.model.enteties.Login. Expected: class java.lang.Long, got class com.utp.soft6.model.enteties.Login
null
    at org.hibernate.event.internal.DefaultLoadEventListener.onLoad(DefaultLoadEventListener.java:132)
    at org.hibernate.internal.SessionImpl.fireLoad(SessionImpl.java:1079)
    at org.hibernate.internal.SessionImpl.access$2200(SessionImpl.java:172)
    at org.hibernate.internal.SessionImpl$IdentifierLoadAccessImpl.getReference(SessionImpl.java:2402)
    at org.hibernate.internal.SessionImpl.load(SessionImpl.java:967)
    at com.utp.soft6.model.LoginDAO.find(LoginDAO.java:26)
    at com.utp.soft6.hola.BuscaCorreo(hola.java:65)
    at com.utp.soft6.hola.doGet(hola.java:47)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:222)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
    at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:502)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:99)
    at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:953)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408)
    at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1023)
    at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:589)
    at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:310)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
    at java.lang.Thread.run(Thread.java:722)

最佳答案

错误消息是不言自明的:

Provided id of the wrong type for class com.utp.soft6.model.enteties.Login. Expected: class java.lang.Long, got class com.utp.soft6.model.enteties.Login

这意味着,当您在以下行中通过 ID 加载登录时

login = (String) session.load(Login.class, id);

您传递一个登录实例 (id) 作为参数,而不是传递登录实体 ID 类型的实例:Long。

此外,Session.load() 返回实体的实例,而不是字符串,因此上面的行根本没有意义。

正确的方法是:

/**
 * Loads and returns the Login entity identified by the given identifier 
 */
public Login find(long id) {
    return (Login) session.load(Login.class, id);
}

您的代码中还有其他大问题,例如在每个请求时读取配置并初始化 Hibernate,而不是只执行一次。

阅读手册。

关于java - 选择值时 hibernate 出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17533063/

相关文章:

java - 如何使用Spring云数据流转换Mysql数据http调用?

php - 如何使用 Laravel 5/Eloquent/query builder 让所有用户按他们的评分排序

MySql查询脚本统计每个月的活跃用户数

php - Magento更新每商店价格查看SQL

java - Multi-Tenancy 应用程序的数据源

java - 我们可以使用类型名称作为变量吗

Java Google Docs API - 在独立 java 程序中使用的文档转换工具

java - 在 JPA 中分离对象

java - Envers - 插入 @NotAudited 字段的实际值

java - Hibernate 将两个表映射到一个类