我正在尝试获取特定日期之间一周中每一天的行数。
到目前为止我已经:
SELECT DATENAME(weekday,Date) AS theDay FROM tablename WHERE year(date) = '2013' and (month(date) >= 5 AND month(date) <= 7)
这给了我这样的东西:
Wednesday
Wednesday
Wednesday
Wednesday
Wednesday
Thursday
Thursday
Friday
Friday
Friday
Friday
Saturday
Saturday
但我希望它是这样的
Wednesday
然后在下一列
5
等等。我知道这是一个分组依据，但我不太擅长 SQL。
最佳答案
SELECT DATENAME(weekday,Date) AS theDay,count(*) NumberOfDays
FROM tablename
WHERE year(date) = '2013' and (month(date) >= 5 AND month(date) <= 7)
group by DATENAME(weekday,Date)
关于mysql - SQL 按 DATENAME 分组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/17975359/