对于单个表，我通常会这样做:
$length = 42;
$result = mysql_query ('SELECT * FROM table WHERE length = "' . $length . '"', $dbconn);
$rowsfound = mysql_num_rows ($result);
if ($rowsfound == 1) {
$row = mysql_fetch_array ($result);
$tableid = $row ['table_id'];
$tablecloth = $row ['tablecloth'];
$height = $row ['height'];
...
但是如何从连接表中获取行，如下所示:
$chairid = 123;
$result = mysql_query ('SELECT * FROM table,chair WHERE chair.id = "' . $chairid . '" AND table.table_id = chair.table_id', $dbconn);
$rowsfound = mysql_num_rows ($result);
if ($rowsfound == 1) {
$row = mysql_fetch_array ($result);
$tableid = $row ['table.table_id'];
$tablecloth = $row ['table.tablecloth'];
$height = $row ['table.height'];
...
这不会返回 $table.tablecloth 中的任何值。我做错了什么？
最佳答案
使用 JOIN 来执行此操作
SELECT * FROM table
INNER JOIN chair ON table.table_id = chair.table_id
WHERE chair.id = "' . $chairid . '"
关于php - 如何从 PHP 中的连接表中获取列？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/18006661/