就我而言,我有来自多个表的数据,我想提取单个查询。这是关于足球统计的。一分钟表记录了比赛的日期,其他记录了比赛的数据和结果。 问题是我想限制日期的应用,而不是比赛的数量,因为一天有几场比赛。 设法构建一个复杂的查询来显示我的所有数据,但它显示游戏数量而不是日期的结果,所以我不能使用限制,因为在这种情况下吃饭变成更多游戏而不是日期。 我的问题是是否可以构建一个对日期有限制的应用程序,同时显示该日期内进行的所有比赛的结果? 这是我现在使用的应用程序的代码:
SELECT
MAIN.id,
SECTION.type,
MAIN.date as date_,
MAIN.prognosis,
HOME_TEAM.team_name as home_team,
GUEST_TEAM.team_name as guest_team,
FIRST_INDEX.index as f_index,
SECOND_INDEX.index as s_index,
THIRD_INDEX.index as t_index,
DATA.home_result,
DATA.guest_result,
DATA.coefficient,
DATA.success,
MAIN.total_coefficient,
MAIN.total_success
FROM ssdt_matches_main as MAIN
LEFT JOIN ssdt_section_type as SECTION ON (MAIN.type_id = SECTION.id)
LEFT JOIN ssdt_matches_data as DATA ON (DATA.matches_main_id = MAIN.id )
LEFT JOIN ssdt_matches_teams as HOME_TEAM ON (HOME_TEAM.id = DATA.home_team_id )
LEFT JOIN ssdt_matches_teams as GUEST_TEAM ON (GUEST_TEAM.id = DATA.guest_team_id )
LEFT JOIN ssdt_matches_index as FIRST_INDEX ON (FIRST_INDEX.id = DATA.first_index_id )
LEFT JOIN ssdt_matches_index as SECOND_INDEX ON (SECOND_INDEX.id = DATA.second_index_id )
LEFT JOIN ssdt_matches_index as THIRD_INDEX ON (THIRD_INDEX.id = DATA.third_index_id )
WHERE SECTION.type = 'Risk prognosis'
ORDER BY MAIN.id DESC
最佳答案
您想要限制 where
子句中的日期,例如:
where MAIN.date between date('2012-01-01') and date('2012-12-31');
如果您想获取最近 10 天(有一场比赛)的记录,您可以执行以下操作:
select . . .
from . . . join
(select date
from ssdt_matches_main md
group by date
order by date desc
limit 10
) datel
on datel.date = MAIN.date
这使用联接来选择日期列表,然后使用联接来进行过滤。
编辑:
您的 from
子句如下所示:
FROM ssdt_matches_main as MAIN
LEFT JOIN ssdt_section_type as SECTION ON (MAIN.type_id = SECTION.id)
LEFT JOIN ssdt_matches_data as DATA ON (DATA.matches_main_id = MAIN.id )
LEFT JOIN ssdt_matches_teams as HOME_TEAM ON (HOME_TEAM.id = DATA.home_team_id )
LEFT JOIN ssdt_matches_teams as GUEST_TEAM ON (GUEST_TEAM.id = DATA.guest_team_id )
LEFT JOIN ssdt_matches_index as FIRST_INDEX ON (FIRST_INDEX.id = DATA.first_index_id )
LEFT JOIN ssdt_matches_index as SECOND_INDEX ON (SECOND_INDEX.id = DATA.second_index_id )
LEFT JOIN ssdt_matches_index as THIRD_INDEX ON (THIRD_INDEX.id = DATA.third_index_id )
join (select date
from ssdt_matches_main md
group by date
order by date desc
limit 10
) datel
on datel.date = MAIN.date
关于mysql - 复杂的mysql查询可能会构建子查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18079082/