我有以下查询:
$result = query("SELECT IdUser, followingID FROM following WHERE IdUser = '%d' AND followingID = '%d'", $id, $followingID);
我想知道如果关系存在的话,如果根据 0 和 1 计数结果为"is"或“否”,我将如何返回?
最佳答案
这是一种方法:
select (case when exists (SELECT IdUser, followingID
FROM following
WHERE IdUser = '%d' AND followingID = '%d'
)
then 'YES' else 'NO'
end) as YesOrNo
, $id, $followingID
关于php - 返回是或否 PHP 查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18093538/