php - 如何在 CakePHP 中获取 "OR"条件？

Question

我正在尝试创建一个匹配特定条件或匹配确切 ID 的查询

这是我想要的查询:

SELECT * WHERE (`Listing.Color` = 'red' AND `Listing.Doors` = 2) OR Listing.ID = 75

这是我在调试时得到的查询:

SELECT * WHERE `Listing.Color` = 'red' AND `Listing.Doors` = 2 AND Listing.ID = 75

这是我的代码:

$conditions = array();

$conditions[] = array('Listing.Color' => 'red');
$conditions[] = array('Listing.Doors' => 4);

$conditions[] =  array( 
        "OR" => array(
            array('Listing.ID' => 75)
             ),
         );

return $conditions;

$this->paginate = array(
    'conditions' => $conditions,
);    


$this->set('listings', $this->paginate());

我也尝试过这些组合(以及其他一些组合)

$conditions["OR"][] = array('Listing.ID' => 75);
$conditions[]["OR"] = array('Listing.ID' => 75);
$conditions[]["OR"][] = array('Listing.ID' => 75);
$conditions["OR"][] = array('Listing.ID' => 75);

Answer 1

$conditions = array(
    'OR' => array(
         array('Listing.Color' => 'red', 'Listing.Doors' => 4),
         array('Listing.ID' => 75)
     )        
);

$this->paginate = array(
    'conditions' => $conditions,
);

另外，为什么在创建 $conditions 数组后就需要 return $conditions; ？