我不想在结果中使用 r.reguser_id 作为测试列，如果我从 Select 语句中删除此列，那么我在 WHERE bu.business_id = r.reguser_id 中遇到问题 strong> 并收到 More then 1 row Returns.
错误SELECT r.reguser_name , r.reguser_id as test,
(Select r.reguser_id as c, GROUP_CONCAT(i.industry_name) as Industry
From reguser r inner JOIN business_industry bu ON r.reguser_id = bu.business_id join industry i ON bu.industry_id = i.industry_id
WHERE bu.business_id = test
GROUP BY bu.business_id
) as indus
FROM reguser r
请告诉我如何解决这个问题？ 谢谢。
最佳答案
SELECT r.reguser_name , r.reguser_id,
(Select r1.reguser_id as c, GROUP_CONCAT(i.industry_name) as Industry
From reguser r1 inner JOIN business_industry bu ON r1.reguser_id = bu.business_id join industry i ON bu.industry_id = i.industry_id
WHERE bu.business_id = r.reguser_id
GROUP BY bu.business_id
) as indus
FROM reguser r
主表和子查询中的表不要使用相同的别名。这确实是不好的做法
关于mysql - 在子查询中获取值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/22499919/