PHP 插入 if 条件

Question

我需要一些特殊字符的 if 条件。所以我基本上想要的是添加某种 'if letter is oe make letter = "ø"' 语句。我怎样才能实现这个目标？

public function letter_get($letter)
    {
        $this->load->database();

        if($letter == '0-9')
        {
            $where = "formated_name LIKE '0%' OR formated_name LIKE '1%' OR formated_name LIKE '2%' 
            OR formated_name LIKE '3%' OR formated_name LIKE '4%' OR formated_name LIKE '5%' OR formated_name LIKE '6%' OR formated_name LIKE '7%' OR formated_name LIKE '8%' OR formated_name LIKE '9%' OR formated_name LIKE '#%'";
        }
        else  
        {
            $where = "formated_name LIKE '".$letter."%'";
        }

        $sql = "SELECT artist_id, formated_name FROM artists WHERE ".$where;
        $query = $this->db->query($sql);
        $data = $query->result();

        if($data) {
            $this->response($data, 200); 
        } else {
            $this->response(array('error' => 'Couldn\'t find any artists with this letter!'), 404);
        }
    }

那么有人可以帮我吗？那太好了! 提前致谢...

Answer 1

您可以使用str_replace替换特殊字符:

$letter = str_replace(array('oe', ... more inputs),
                      array('ø', ... more replacements),
                      $letter);