mysql - SQL 表更新每个 Id 的除最新记录之外的所有记录

Question

考虑下表，其中有 4 个不同的客户，每个客户的订单都超过 1 个。 我需要根据创建列的日期将每个客户的 XYZ 列更新为 1。

Update the table1 set xyz = 1

仅条件是最新(创建日期)订单的 XYZ 值为 0

Customerid  Orderid     Date Created       XYZ 
12193438    13393354    09/08/2011 16:35    0
12193438    13384318    05/08/2011 14:08    0
12193438    13384458    08/08/2011 14:01    0
21801966    13379456    06/08/2011 12:59    0
21801966    13380639    06/08/2011 16:42    0
21971567    13385322    22/08/2011 18:00    0
21971567    13380200    09/08/2011 21:03    0
66697824    13389263    07/08/2011 13:44    0
66697824    13380162    08/08/2011 15:48    0

它应该如下所示

Customerid  Orderid       Date Created     XYZ
12193438    13393354    09/08/2011 16:35    0
12193438    13384318    05/08/2011 14:08    1
12193438    13384458    08/08/2011 14:01    1
21801966    13379456    06/08/2011 12:59    1
21801966    13380639    06/08/2011 16:42    0
21971567    13385322    22/08/2011 18:00    0
21971567    13380200    09/08/2011 21:03    1
66697824    13389263    07/08/2011 13:44    1
66697824    13380162    08/08/2011 15:48    0

Answer 1

UPDATE thetable tt
SET xyz = 1
WHERE EXISTS (
  SELECT * FROM thetable ex
  WHERE ex.customerId = tt.customerId
  AND ex.dateCreated > tt.dateCreated
  );