我的表格如下所示:
ID | click | time | browser
1 1 [01:00:00] FireFox
2 1 [01:00:00] FireFox
3 0 [01:00:00] Opera
4 1 [02:00:00] FireFox
5 1 [02:00:00] Chrome
6 1 [02:00:00] Chrome
所以输出应该是:
01:00:00
Total hits: 3
Clicks: 2
FireFox: 2
Opera: 1
02:00:00
Total hits: 3
Clicks: 3
FireFox: 1
Chrome: 2
我知道如何在没有浏览器的情况下获得它:
SELECT SUM(click) AS click, COUNT(*), HOUR(time)
FROM hits
WHERE time >= DATE_SUB(NOW(),INTERVAL 24 HOUR) GROUP BY HOUR(time)
但我不知道用浏览器输出这个。 如果浏览器不被分组并且我得到如下输出,我根本不介意:
01:00:00
Total hits: 3
Clicks: 2
02:00:00
Total hits: 3
Clicks: 3
-----------
FireFox: 3
Chrome: 2
Opera: 1
最佳答案
您可以使用IF
:
SELECT SUM(`click`) AS click
, COUNT(*)
, HOUR(`time`)
, COUNT(IF( `browser` = 'Chrome', `browser`, null)) AS `Chrome`
, COUNT(IF( `browser` = 'Opera', `browser`, null)) AS `Opera`
, COUNT(IF( `browser` = 'FireFox', `browser`, null)) AS 'FireFox'
FROM `hits`
WHERE `time` >= DATE_SUB(NOW(),INTERVAL 24 HOUR)
GROUP BY HOUR(`time`)
或案例
:
SELECT SUM(`click`) AS click
, COUNT(*)
, HOUR(`time`)
, COUNT(CASE WHEN `browser` = 'Chrome' THEN `browser` END) AS `Chrome`
, COUNT(CASE WHEN `browser` = 'Opera' THEN `browser` END) AS `Opera`
, COUNT(CASE WHEN `browser` = 'FireFox' THEN `browser` END) AS 'FireFox'
FROM `hits`
WHERE `time` >= DATE_SUB(NOW(),INTERVAL 24 HOUR)
GROUP BY HOUR(`time`)
关于PHP MySQL : COUNT/SUM a non integer column with different values,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24108199/