android - android中通过url传递多个参数并在PHP中获取

Question

在我的 Android 应用程序中，我已使用 JSON over AsyncHttp 协议(protocol)将 sqlite 数据传递到远程 mysql 数据库。
现在我想要从 Mysql 数据库到 SQLite 数据库的数据，以便从服务器获取数据并将其转换为 JSON。
由于服务器有很多行数据，我只需要获取我的手机 SQLite 数据，以便我需要传递变量并检查数据是否是我的，而不是获取所有用户数据。

如何传递 url 中的变量，以便在仅获取时搜索我的用户数据并将其插入 SQLITE 数据库。
这是我的代码

public void syncMySQLDBSQLite(){
            // Create AsycHttpClient object
            AsyncHttpClient client = new AsyncHttpClient();
            // Http Request Params Object
            RequestParams params = new RequestParams();
            // Show ProgressBar
            prgDialog.show();
            // Make Http call to getusers.php
            client.post("http://10.0.2.2/tafapps/getuser.php", params, new AsyncHttpResponseHandler() {
                    @Override
                    public void onSuccess(String response) {
                        // Hide ProgressBar
                        prgDialog.hide();
                        // Update SQLite DB with response sent by getusers.php
                        updateSQLite(response);

                    }
                    // When error occured
                    @Override
                    public void onFailure(int statusCode, Throwable error, String content) {
                        // TODO Auto-generated method stub
                        // Hide ProgressBar
                        prgDialog.hide();
                        if (statusCode == 404) {
                            Toast.makeText(getApplicationContext(), "Requested resource not found", Toast.LENGTH_LONG).show();
                        } else if (statusCode == 500) {
                            Toast.makeText(getApplicationContext(), "Something went wrong at server end", Toast.LENGTH_LONG).show();
                        } else {
                            Toast.makeText(getApplicationContext(), "Unexpected Error occcured! [Most common Error: Device might not be connected to Internet]",
                                    Toast.LENGTH_LONG).show();
                        }
                    }
            });
        }

         public void updateSQLite(String response){
                ArrayList<HashMap<String, String>> usersynclist;
                usersynclist = new ArrayList<HashMap<String, String>>();
                // Create GSON object
                Gson gson = new GsonBuilder().create();
                try {
                    // Extract JSON array from the response
                    JSONArray arr = new JSONArray(response);
                    Toast.makeText(getApplicationContext(), response, 5000).show();
                    System.out.println(arr.length());
                    // If no of array elements is not zero
                    if(arr.length() != 0){
                        // Loop through each array element, get JSON object which has userid and username
                        for (int i = 0; i < arr.length(); i++) {
                            // Get JSON object
                            JSONObject obj = (JSONObject) arr.get(i);
                            System.out.println(obj.get("userId"));
                            System.out.println(obj.get("userName"));
                            db = this.openOrCreateDatabase("Hangman", MODE_PRIVATE, null);

                           // String id =  obj.get("userId").toString();
                             name =  obj.get("userName").toString();
                             email = obj.get("userEmail").toString();
                             phn = obj.get("userPhnum").toString();
                             plyd = obj.get("userPlayed").toString();
                             crct = obj.get("userCorrect").toString();
                            //Toast.makeText(getApplicationContext(), email, 5000).show();

                            db.execSQL("insert into scores(userName,userEmail,userPhnum,userPlayed,userCorrect)values('"+name+"','"+email+"','"+phn+"','"+plyd+"','"+crct+"')");
                        }
                        //Toast.makeText(getApplicationContext(), ""+queryValues, 5000).show();
                        // Inform Remote MySQL DB about the completion of Sync activity by passing Sync status of Users
                        updateMySQLSyncSts(gson.toJson(usersynclist));
                    }
                } catch (JSONException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
            }

Answer 1

使用 HTTP GET 或 POST 请求。 带参数的 GET 示例: http://example.com/tafapps/getuser.php?user=user1&user_age=21

在 POST 请求中，此参数在 URL 中不可见，而是在请求正文中进行编码。

您可以使用parse_url()和parse_str()进行解析:

$parts = parse_url($url);
parse_str($parts['query'], $query);
echo $query['user'];

或者据我所知更好:

$user = $_GET['user']

PHP Manual: Predefined _GET variable