php - 从其他查询mysql的结果生成结果

Question

这是我的 table

从上面

我的查询是

SELECT count_id, COUNT( questionID ) AS qid
FROM `sg_count`
GROUP BY count_id

它将得到输出

我还想使用第一个查询的结果来计算(count_id)谁拥有qid <5

Answer 1

试试这个 -

"SELECT count(qid) FROM (
    SELECT count_id, COUNT( questionID ) AS qid FROM `sg_count` GROUP BY count_id
) as count_data where qid < 5" ;