嘿,大家好,我正在尝试保存用户在表单上选择的选项,但我不确定如何执行此操作。
我将简要解释我的设置...
我的主页上有此表格:
<form class="form-home form-search">
<select class="form-control select-box">
<option value="make-any">Make (Any)</option>
<?php while($make = $makeFilter->fetch(PDO::FETCH_ASSOC))
{
echo '
<option value="'.$make["Make"].'">'.$make["Make"].'</option>
';
} ?>
</select>
<button href="used-cars.php">Search</button>
</form>
如您所见,它使用 PHP/MySQL 来显示可用选项。
好的,然后我将这个表单放在另一个页面上,但是 CSS 样式略有不同,并且它包含一些不同的选择元素。
因此,当用户选择主页上的某个元素时,按钮所做的所有操作都是 href 到列出所有结果的used-cars.php。
如何才能使 jQuery 保存用户在主页上选择的选项并加载选择的这些选项的used-cars.php?
任何例子都会很棒。
已编辑 我的第二种形式的示例:
<div class="container con-col-listing">
<div class="row">
<div class="col-md-4 col-sm-4">
<form class="car-finder-container dflt-container">
<h2 class="h2-finder">Car finder</h2>
<ul class="toggle-view">
<li class="li-toggle">
<h4 class="h4-finder-toggle">Make<span class="glyphicon glyphicon-plus glyph-plus-toggle"></span></h4>
<div class="panel">
<select name="make" class="form-control select-box">
<option value="make-any">Make (Any)</option>
<?php while($make = $makeFilter->fetch(PDO::FETCH_ASSOC)){
$selected = $make['make'] == $_GET['make']?'selected="selected"':'';
echo '
<option value="'.$make["Make"].'">'.$make["Make"].'</option>
';
} ?>
</select>
<select class="form-control last-select select-box">
<option value="model-any">Model (Any)</option>
<?php while($model = $modelFilter->fetch(PDO::FETCH_ASSOC))
{
echo '
<option value="'.$model["Model"].'">'.$model["Model"].'</option>
';
} ?>
</select>
</div>
</li>
<li class="li-toggle">
<h4 class="h4-finder-toggle">Body type<span class="glyphicon glyphicon-plus glyph-plus-toggle"></span></h4>
<div class="panel">
<input id="four-by-four-checkbox" class="float-checkbox" type="checkbox"/>
<label for="four-by-four-checkbox" class="label-checkbox">4x4</label>
<input id="convertible-checkbox" class="float-checkbox" type="checkbox"/>
<label for="convertible-checkbox" class="label-checkbox">Convertible</label>
<input id="coupe-checkbox" class="float-checkbox" type="checkbox"/>
<label for="coupe-checkbox" class="label-checkbox">Coupe</label>
</div>
</li>
<li class="li-toggle">
<h4 class="h4-finder-toggle">Transmission<span class="glyphicon glyphicon-plus glyph-plus-toggle"></span></h4>
<div class="panel">
<input id="automatic-checkbox" class="float-checkbox" type="checkbox"/>
<label for="automatic-checkbox" class="label-checkbox">Automatic</label>
<input id="manual-checkbox" class="float-checkbox" type="checkbox"/>
<label for="manual-checkbox" class="label-checkbox">Manual</label>
<input id="semi-auto-checkbox" class="float-checkbox" type="checkbox"/>
<label for="semi-auto-checkbox" class="label-checkbox">Semi automatic</label>
</div>
</li>
</ul>
<button href="#" class="btn btn-block car-search-button btn-lg btn-success"><span class="glyphicon car-search-g glyphicon-search"></span> Search cars
</button>
<h4 class="h4-finder"><a href="#">Try our Smart Search </a><span class="glyphicon info-car-search-g glyphicon-info-sign"></span></h4>
</form>
</div>
最佳答案
最简单的方法是使用 get 请求:
<form class="form-home form-search" method="GET" action="used-cars.php">
<select name="make" class="form-control select-box">
.....
<button type="submit">Search</button>
</form>
以及used-cars.php:
var_dump($_GET['make']);
编辑
让我们假设第一页上的表单:
<option value="ford">ford</option>
<option value="pontiac">pontiac</option>
<option value="fiat">fiat</option>
当您点击used-cars.php上的提交按钮$_GET['make']
时,将是选择的任何内容,比如fiat
。
现在在used-cars.php 上你可以这样做:
<?php while($make = $makeFilter->fetch(PDO::FETCH_ASSOC)){
$selected = $make['Make'] == $_GET['make']?'selected="selected"':'';
echo '
<option '.$selected.' value="'.$make["Make"].'">'.$make["Make"].'</option>
';
} ?>
关于javascript - jQuery:保存已选择的选择元素选项,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26083987/