php - 如果行值类似于第一行，则如何自动递增 1 并附加小数，否则为 2

Question

我有这个代码来生成连接两个表的报告。

$agebracket= $_POST['age_bracket'];   //coming from dropdown list

$sql=mysql_query("select qshortcode from question_details  where pans1 like '%$agebracket%'");
while($row=mysql_fetch_array($sql)){

 $utility[] = preg_replace('/[0-9]+/','',$row['qshortcode']);              
}
$slno=0;
for($i=0;$i<count($utility);$i++) {
$last=""; //as suggested
$check=mysql_query("select q.qshortcode,q.qcode,q.question,p.paid_rev from question_details q left outer join paid_response p on q.qcode=p.qno where q.qshortcode like '$utility[$i]%' group by q.qcode");
    while($qscode=mysql_fetch_array($check)) {  

      if($last =substr($qscode['qcode'],strlen($last))) { 
       $last = $qscode['qcode'];          
       $slno++;
       $slid = $slno ;
      } else {
        $slid .= ".1";
      }

      echo "<tr>";
      echo "<td>".$slid.' '."</td>";
      echo "<td>".$qscode['qshortcode'].' '."</td>";
      echo "<td>".$qscode['qcode'].' '."</td>";
      echo "<td>".$qscode['question'].' '."</td>";
      echo "<td>".$qscode['paid_rev']."<br></td>";
      echo "</tr>";       
    }       
}
echo "</table>";

这会生成此报告，该报告从带有左外连接的两个表中获取，还获得空白收入

SL-No   Qcode     Question    Revenue
  1      test     whatever    
  1.1    test_1   zzz         
  2      test_2   xxx         something    //here it is becoming 2 but it should be 1.1.1
  3      abc      vvv         
  3.1    abc1     khkhk       something

现在实际上我想用 1 自动递增 SL-No 那么如果 qcode 与第一行 qcode 匹配，它将是 1.1然后 1.1.1 然后当它不匹配时它将是 2。就像报告一样

SL-No      Qcode      Question    Revenue
  1         test      whatever    
 1.1       test_1      zzz         
 1.1.1     test_2      xxx         something
  2         abc        vvv         
 2.1       abc1        khkhk       something

Answer 1

我会做这样的事情(未经测试的代码):

$slno=0;
[...] // for loop omitted, just starting at 0 instead of 1, to increment properly after.
$last="-1"; // To avoid comparing two empty lines at first pass, which will obvisouly be alway true, sorry.
while ([mysql query ....]) {
  if ($last != substr($qscode['qcode'],0, strlen($last))) {
    $last = $qscode['qcode'];
    $slno++;
    $slid = strval($slno)
  } else {
   $slid .= ".1"
  }

  echo "<tr>";
  echo "<td>".$slid.' '."</td>";
  echo "<td>".$qscode['qshortcode'].' '."</td>";
  [...] // rest omitted
}