我正在将一个项目迁移到 Laravel 4,但我遇到了一个相当复杂的查询,我想将其迁移到正确的 Eloquent 查询中。
我有一个包含聊天消息的表,名为 chat_messages
,带有表示模型 Chatmessage
该表包含一个发送者列和一个接收者列,其中的用户 ID 链接到 users
表和 User
模型。
在旧版本应用程序上使用原始 SQL 获取包含所有聊天伙伴的所有用户 ID 的列表的查询如下:
$sql_allChatPartners = "SELECT DISTINCT chatPartner
FROM ( SELECT * FROM (
SELECT cm_receipient AS chatPartner, cm_sent_at
FROM chat_messages WHERE cm_sender = '".$me->userID."'
UNION
SELECT cm_sender AS chatPartner, cm_sent_at
FROM chat_messages WHERE cm_receipient = '".$me->userID."'
) whateva ORDER BY whateva.cm_sent_at DESC ) other";
很抱歉将“假”表命名为whateva和其他:-)
有人能给我正确的方向来使用 Eloquent Querybuilder 执行此操作吗?
重要的是,我必须以正确的顺序获取 chatPartner ID 列表,其中最后一条聊天消息已作为第一个 chatPartner 进行交换。聊天中不活动时间最长的聊天伙伴作为最后一个条目。
这是我迄今为止在用户模型中得到的......
public function allopenchats(){
$asSender = Chatmessage::where('sender', $this->id)->select('receipient as chatPartner, created_at');
$asBoth = Chatmessage::where('receipient', $this->id)->select('sender as chatPartner, created_at')
->union($asSender)->orderBy('created_at', 'desc')->get();
}
我将列 cm_receipient
重命名为 receipient
,将 cm_sender
重命名为 sender
和 sent_at
> 到新版本的新数据库中的created_at
非常感谢您的帮助!
最佳答案
您的sql可能会更改为:
SELECT IF (cm_receipient = '10', cm_sender, IF (cm_sender = '10',cm_receipient, 'no')) AS chatPartner, cm_sent_at
FROM chat_messages
WHERE cm_receipient = '10' OR cm_sender = '10'
GROUP BY chatPartner
HAVING chatPartner != 'no'
按 cm_sent_at DESC 排序
正常情况下:
Chatmessage::where('sender','=',$this->id)
->orWhere('receipient','=',$this->id)
->select(DB::raw('IF (receipient = '.$this->id.', sender, IF (sender = '.$this->id.',receipient, 'no' )) AS chatPartner'), 'created_at')
->groupBy('chatPartner')
->having('chatPartner', '!=', 'no')
->orderBy('created_at', 'desc')
->get();
关于mysql - Eloquent 查询构建复杂查询以获取在同一表的 2 个不同列中搜索 ID 的唯一记录,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28604940/