我使用 PHP 和 mysql 制作了一个小型消息系统。我已在消息表中将我的用户链接为sender
和receiver
。我可以列出两个用户之间的对话。但我无法找到一种方法来显示每次对话的 1 条消息结果!
假设我有用户 1、2 和 3。所以我的消息表可能如下所示:
===================================================================
ID || sender || receiver || text || date
===================================================================
1 || 1 || 2 || Hello! || timestamp stuff
2 || 2 || 1 || Hi! ||
3 || 1 || 3 || Boo! ||
因此对话链接为
SELECT * FROM messages WHERE (sender=1 OR sender=2) AND (receiver=1 OR receiver=2);
这样我就可以得到两个用户之间的完整对话(非常简单)。
回到问题,如何从每个对话中获取 1 条消息?
我尝试过这样的事情:
(SELECT m.text,m.date,sender.username,receiver.username
FROM messages AS m
INNER JOIN users AS sender on m.sender=user.ID
INNER JOIN users AS receiver ON receiver.ID=m.receiver
WHERE m.sender=1 OR m.receiver=1
ORDER BY messages.date DESC LIMIT 1);
但显然这并没有达到我想要的效果,因为只返回一行。我想我知道我需要做什么,只是不知道该怎么做? 我想我需要这样的东西:
SELECT sender.username,receiver.username,m.text,m.date FROM messages AS m
INNER JOIN users AS sender ON sender.ID=m.sender
INNER JOIN users AS receiver ON receiver.ID=m.receiver
LEFT JOIN (SELECT mes.ID
FROM messages AS mes
WHERE mes.sender=1 OR mes.receiver=1
ORDER BY mes.date DESC LIMIT 1) AS convo
ON convo.ID=m.ID;
这样的东西有用吗?
如果你想查看我的完整 sql:
(SELECT sender.ID AS senderID,sender.username AS senderUsername,sender.firstname AS senderFirstname,sender.lastname AS senderLastname,sender.othername AS senderOthername,sender.url_name AS senderUrl_name,senderI.path as sender_default_image,
receiver.ID AS receiverID,receiver.username AS receiverUsername,receiver.firstname AS receiverFirstname,receiver.lastname AS receiverLastname,receiver.othername AS reciverOthername,receiver.url_name AS recieverUrl_name,receiverI.path as reciever_default_image,
messages.message,messages.date,messages.read
FROM '.$wpdb->prefix.'fishy_messages AS messages
INNER JOIN '.$wpdb->prefix.'fishy_users AS sender ON sender.ID=messages.sender
LEFT JOIN '.$wpdb->prefix.'fishy_profile_default_image AS senderDP ON senderDP.userID=sender.ID
INNER JOIN '.$wpdb->prefix.'fishy_users AS receiver ON receiver.ID=messages.receiver
LEFT JOIN '.$wpdb->prefix.'fishy_profile_default_image AS receiverDP ON receiverDP.userID=receiver.ID
LEFT JOIN '.$wpdb->prefix.'fishy_images AS senderI ON senderI.ID=senderDP.imageID
LEFT JOIN '.$wpdb->prefix.'fishy_images AS receiverI ON receiverI.ID=receiverDP.imageID
WHERE messages.sender=%d OR messages.receiver=%d ORDER BY messages.date DESC LIMIT 1)
是的,我正在使用 wordpress :p
最佳答案
要返回单个结果,请在外部查询上指定 Limit 1
,您已在 INNER 查询中给出。
SELECT sender.username,receiver.username,m.text,m.date FROM messages AS m
INNER JOIN users AS sender ON sender.ID=m.sender
INNER JOIN users AS receiver ON receiver.ID=m.receiver
LEFT JOIN (SELECT mes.ID
FROM messages AS mes
WHERE mes.sender=1 OR mes.receiver=1
ORDER BY mes.date DESC LIMIT 1) AS convo
ON convo.ID=m.ID GROUP BY convo.ID ;
关于php - 消息系统,显示对话列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33199819/