python - 获取Python列表的当前索引

Question

我目前有以下内容:

jsonfiletext = jsonfile.read()
data = json.loads(jsonfiletext)
cursor.execute("SELECT CheckinID FROM checkins ORDER BY CheckinID DESC LIMIT 1")
for row in cursor.fetchall():
    checkin_id = row[0]
for checkin in data:
    ~do stuff~

数据如下所示:

[{u'abc': u'123', u'def': u'456'}, {u'abc': u'789', u'def': u'012'}]

但是，我希望在字典中获取某种形式的索引或键。

jsonfiletext = jsonfile.read()
data = json.loads(jsonfiletext)
cursor.execute("SELECT CheckinID FROM checkins ORDER BY CheckinID DESC LIMIT 1")
for row in cursor.fetchall():
    checkin_id = row[0]
for checkin in data:
    if checkin.index() > checkin_id:
        ~do stuff~

基本上，我想根据数据库中已有的内容避免重复。

checkin.index() 如下:

1. {u'abc': u'123', u'def': u'456'}
2. {u'abc': u'789', u'def': u'012'}

Answer 1

你是这个意思吗？

>>> my_dict = {'age': 18, 'name': 'jhon', 'sex': 'm'}
>>> for index,item in enumerate(my_dict.items()):
        print index, dict([item])
0 {'age': 18}
1 {'name': 'jhon'}
2 {'sex': 'm'}

<小时/>

编辑:

>>> data = [{u'abc': u'123', u'def': u'456'}, {u'abc': u'789', u'def': u'012'}]
>>> for item_with_index in enumerate(data):
        print item_with_index
(0, {u'abc': u'123', u'def': u'456'})
(1, {u'abc': u'789', u'def': u'012'})