php - 如何按last_visit排序并显示用户的最近访问者？

Question

以下公共(public)函数显示用户个人资料的访问者。我想做的是按最近的访问者对结果进行排序。我认为最好的方法是在左 JOIN 之前添加 ORDER BY last_visit。但这破坏了脚本，我收到“无结果”消息。顺便说一句，last_visits 有一个时间戳数据类型。

public function getVisitors($count = 10, $page = 0){
    $result = $this->_db->query('
        SELECT
            `visited_users`.*,
            `users`.*,
            NOW() as now_t
        FROM
            `visited_users`
        ORDER BY last_visit  
        LEFT JOIN `users` ON `users`.`id` = `visited_users`.`user_id`
        WHERE
            `visited_users`.`visited_id` = ?
        LIMIT '.$count*$page.','.$count, array($this->_data->id));
    return $result->results();
}

Answer 1

正确的 SQL 语法要求 ORDER BY 位于 WHERE 子句之后。试试这个。

public function getVisitors($count = 10, $page = 0){
    $result = $this->_db->query('
        SELECT
            `visited_users`.*,
            `users`.*,
            NOW() as now_t
        FROM
            `visited_users`
        LEFT JOIN `users` ON `users`.`id` = `visited_users`.`user_id`
        WHERE
            `visited_users`.`visited_id` = ?
        ORDER BY last_visit  
        LIMIT '.$count*$page.','.$count, array($this->_data->id));
    return $result->results();
}