php - 如何为每个用户循环执行 Codeigniter 中的代码？

Question

我有计算员工总工作时间的代码。 我提供登录条目数组和注销数组。该代码计算员工工作的总小时数、秒数和分钟数。

这是代码:

<?php
                $loginarry = $attendances;
                $logoutarry =$attendances_logouts;
                $timeduration=0;
                $login_i=0;
                $logout_i=0;


                echo '<table border="1px"  class="table table-striped table-bordered table-hover" id="dataTables-example">';
                echo '<tr><th>Login</th><th>Logout</th><th>Duration</th></tr>';

                //echo ("Array Length = " . count($loginarry)." & ".count($logoutarry)."\n<br/>");
        while(true)
        { 
            if( $login_i >= count($loginarry) && $logout_i >= count($logoutarry))
                break;

            if( $logout_i >= count($logoutarry))
            {
                //echo ("Login[".$login_i."] : ".$loginarry[$login_i]->date_data." and Logout : -----------------\n<br/>");


echo ("<tr><td>".$loginarry[$login_i]->date_data." </td><td>Not Available</td><td>Not Available</td></tr>");


    //          echo ("<tr> <td>".$loginarry->date_data." </td><td> Data Not Available</td></tr>");
                $login_i++;
                continue;
            }

            if(($login_i+1) == count($loginarry) && ($logout_i+1) < count($logoutarry))
            {
                echo ("<tr><td>Data Not Available </td><td>".$logoutarry[$logout_i]->date_data."\n</td><td>Data Not Available</td></tr>");
            $logout_i++;
            continue;
            }

            if( $login_i >= count($loginarry))
            {
                echo ("<tr><td> Data Not Available </td><td>".$logoutarry[$logout_i]->date_data."\n<td>Data Not Available</td></td></tr>");
                            $logout_i++;
                continue;
            }
            //echo( "******* ".(new DateTime($loginarry[$login_i+1]->date_data))->format('U') . " **** ".(new DateTime($logoutarry[$logout_i]->date_data))->format('U'). "\n<br/>");

            //check if next login time is smaller then current logout time - if so skip current login time
            if($login_i < (count($loginarry)-1) && (new DateTime($logoutarry[$logout_i]->date_data))->format('U') > (new DateTime($loginarry[$login_i+1]->date_data))->format('U'))
            //if( date_diff(date_create($logoutarry[$logout_i]->date_data), date_create($loginarry[$login_i+1]->date_data)) > 0 )
            {
                echo ("<tr><td>".$loginarry[$login_i]->date_data."</td><td>Data Not Available</td><td>Data Not Available</td></tr>");
                $login_i++;
                continue;
            }

           //
            if( (new DateTime($loginarry[$login_i]->date_data))->format('U') > (new DateTime($logoutarry[$logout_i]->date_data))->format('U') )
            //if( date_diff(date_create($loginarry[$login_i]->date_data), date_create($logoutarry[$logout_i]->date_data)) > 0 )
                    {
                echo ("<tr><td>Data Not Available </td><td>".$logoutarry[$logout_i]->date_data."\n</td><td>Data Not Available</td></tr>");

                            $logout_i++;
                            continue;
                    }

            //if more logout entries then skip to last logout entry
            if( $login_i < (count($loginarry)-1) && $logout_i < (count($logoutarry)-1) && (new DateTime($logoutarry[$logout_i+1]->date_data))->format('U') < (new DateTime($loginarry[$login_i+1]->date_data))->format('U'))
            {
                echo(" <tr><td> Data Not Available</td> <td>".$logoutarry[$logout_i]->date_data."\n</td> <td>Data Not Available</td> </tr>");
                            $logout_i++;
                            continue;
            }

            echo ("<tr><td> ".$loginarry[$login_i]->date_data."</td>  <td>".$logoutarry[$logout_i]->date_data."</td>");




            $singleduration = ((new DateTime($logoutarry[$logout_i]->date_data))->format('U') - (new DateTime($loginarry[$login_i]->date_data))->format('U'));
            if($singleduration > 43200)//12 hours X 3600 seconds)
            {   
                 //$timeduration += $singleduration;
                 echo ("<td class='danger'>Huge duration - not considered - please contact HR (".$singleduration.")</td></tr>");
            }
            else
            {
                 $timeduration += $singleduration;
                 echo ("<td>".gmdate("H:i:s",$singleduration)."</td></tr>");
            }
            $login_i++;
            $logout_i++;

        }

            echo ("</table>");

            //$finaltime=gmdate("H:i:s",$timeduration);
            //$timedurationstr = ConvertSecondsToStr($timeduration);
            $hours = 0;
            if($timeduration > 3600)
            {
                $hours = floor($timeduration/3600);
                $timeduration -= (3600*$hours);
            }
            $min = 0;
            if($timeduration > 60)
            {
                $min = floor($timeduration/60);
                $timeduration -= (60*$min);
            }
            $seconds = $timeduration;



           //echo("<div class= 'row'> <div class ='col-sm-4' style= 'float:right'><h3 class='alert alert-success'><center>Total Hours Worked ". $finaltime." Hours</center></h3></div></div>");
           echo("<div class= 'row'> <div class ='col-sm-4' style= 'float:right'><h3 class='alert alert-success'><center>Total time worked: ". $hours." Hour(s) ".$min." Minute(s) ".$seconds." Second(s)</center></h3></div></div>");
           //echo("<div class= 'row'> <div class ='col-sm-4' style= 'float:right'><h3 class='alert alert-success'><center>Total time worked: ". $timedurationstr." </center></h3></div></div>");

                ?>

最后它返回员工的工作时间。这段代码是我的看法。

现在我想计算数据库中每个用户的这些值。 我不知道如何循环所有用户并运行此代码，以便我可以获得每个用户的总工作时间。

在 Controller 中，我像这样获取用户以及登录和注销条目。

$users = $this->data['users'] = $this->user_m->get();


    $loginarry = $this->data['attendances'] = $this->attendance_m->all_login();
    $logoutarry =$this->data['attendances_logouts'] =$this->attendance_m->all_logout();

        $this->data['subview'] = 'admin/dashboard/index';
        $this->load->view('admin/_layout_main',$this->data);

现在如何显示每个用户的总工作时间？

这是我获取登录和注销条目的代码

ublic function all_login($emp_id = NULL)
{



        $startDate = new DateTime("first day of last month");

        $endDate = new DateTime("last day of last month");

        $emp_id = $this->session->userdata('emp_id');

        $this->db->select('*');

        $this->db->from('daily_data2');


        $this->db->where('entry >','100');

        $this->db->where("date(date_data) BETWEEN '" . $startDate->format( 'Y-m-d' ) . "' AND '" . $endDate->format( 'Y-m-d') . "' ");  

        $this->db->order_by("date_data","ASC");



        $query = $this->db->get();

        $res   = $query->result();        

        return $res;

}




public function all_logout()
{


          $startDate = new DateTime("first day of last month");


          $endDate = new DateTime("last day of last month");



          $emp_id = $this->session->userdata('emp_id');

          $this->db->select('*');

          $this->db->from('daily_data2');



          $this->db->where('entry <','100');
          $this->db->where("date(date_data) BETWEEN '" . $startDate->format( 'Y-m-d' ) . "' AND '" . $endDate->format( 'Y-m-d') . "' ");  

          $this->db->order_by("date_data","ASC");



          $query = $this->db->get();



           $res   = $query->result();        

          return $res;


}

Answer 1

如果您一直都是这样计算的，也许您应该创建一个以出勤率作为参数的函数。然后你可以获取用户列表作为出勤并循环它

public function calculatedTime(attendance){

//Your coding here

}

你可以循环它来获取时间

foreach($loginarry as $att){

     $this->calculatedTime($att);

}

尽量使编码尽可能简单，如果需要重复，只需创建一个函数并调用即可。