我希望计算表中用户出现"is"的次数,然后将结果发布到同一用户的另一个表中。两个表都有用户名。我希望为每个用户完成此操作。我有以下内容,但它不起作用。
$sql = $item_count = "SELECT SUM(if(strike='yes',1,0)) AS strike_total FROM weekpicks WHERE username = 'username'";
// execute SQL query and get result
$sql_result = mysql_query($sql) or die (mysql_error());
if (!$sql_result) {
echo "Something has gone wrong!";
}
else {
//loop through record and get values
while ($row = mysql_fetch_array($sql_result)) {
$item_result = ($row = @mysql_query($item_count)) or die(mysql_error());
$strike_total = ($row = @mysql_result($item_result,"strike_total"));
$strikes = ($row = $strike_total ['strike_total']);
$username = $row["username"];
// the following will insert number of strikes into table for each user.
$sql = "UPDATE authorize SET strikes = '($strikes)' WHERE username='$username'";
//mysql_query(" UPDATE authorize SET " . "strikes = '" . ($strikes) . "' WHERE username='$username' ");
$result = mysql_query($sql) or die (mysql_error());
最佳答案
只需一个查询就足够了
针对单个用户的更新..
UPDATE authorize SET strikes = (select count(*) from weekpicks WHERE username = '$username' and strike='yes') WHERE username='$username';
批量更新所有用户
UPDATE authorize as A SET strikes = (select count(*) from weekpicks B WHERE strike='yes' and A.username=B.username group by B.username)
是不是很简单。
关于php - 更新多个用户的表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35117965/