PHP 和 MySQL 对数据库中的每一行执行操作

Question

我正在构建一个网站，本质上这个 PHP 算法要做的就是一次查看一个产品(MySQL 数据库中的行)，并相应地执行一个过程。

我对此进行了大量研究，但找不到任何东西，任何帮助将不胜感激!

我的代码(当前没有为回显变量返回任何内容):

<?php
include_once 'dbconnect.php';


$query = "SELECT * FROM track"; 
$result = mysql_query($query);


while($row = mysql_fetch_array($result)){ 
    $pro_code = mysql_result(mysql_fetch_array(mysql_query('SELECT product_code FROM track')));
    $currency = mysql_fetch_array(mysql_query('SELECT currency FROM track'));
    $cc = mysql_fetch_array(mysql_query('SELECT cctld FROM track'));
    $initial_price = mysql_fetch_array(mysql_query('SELECT initial_price FROM track'));

    $url = 'test';
}

echo $pro_code;
echo $currency;
echo $initial_price;

?>

Answer 1

首先，有一天尝试一下 Jay Blanchard 提供的有关 PDO 和其他内容的建议。

其次，我已经尝试回答你的问题，并且我已经尝试解释你的完整意图。我在代码中添加了注释:

    <?php
    include_once 'dbconnect.php';

    $query = "SELECT * FROM track"; 
    $result = mysql_query($query);

    while($row = mysql_fetch_array($result)){ 

        //You need to read the row variable as an array
        $pro_code       = $row['product_code'];
        $currency       = $row['currency'];
        $cc             = $row['cctld'];
        $initial_price  = $row['initial_price'];

        //$url is not used.. I asume a test to get the external source ;-)
        $url = 'test';

        if ($url == $cc) {
            //if you want to print every row, you must echo inside the while loop
            echo $pro_code;
            echo $currency;
            echo $initial_price;    
        } elseif ($url == 'test') {
            //do something else here
        } else {
            //do something for all the other cases here
        }//end if

    }//end while
    ?>