我的查询是根据 woks 表(由 3 部分组成)对费用进行求和,结果应该是 13000,但我得到的是 39000。
# Order table
-------------------------------------------
| Id | order | Name | Fee |
-------------------------------------------
| 1 | SELECT STATEMENT | ab | 13000 |
-------------------------------------------
# Work table
-----------------------------
| Id | user id | order id |
-----------------------------
| 1 | 123 | 1 |
| 2 | 123 | 1 |
| 3 | 123 | 1 |
-----------------------------
# Query
SELECT o.order_id, SUM(o.fee) AS total_words
FROM users AS u
LEFT JOIN works AS wr ON wr.user_id = u.id
LEFT JOIN orders AS o ON o.order_id = wr.order_id
WHERE u.id = 123
# Output =>
Array
(
[order_id] => 1
[fee] => 39000
)
我尝试过 DISTINCT 和 group by 但得到了相同的结果。
最佳答案
<强> SQL Fiddle Demo
SELECT `user_id`, SUM(orders.`Fee`)
FROM (SELECT DISTINCT `user_id`, `order_id`
FROM works
) as user_work
JOIN orders
ON user_work.`order_id` = orders.`Id`
WHERE user_work.user_id = 123
输出
| user_id | SUM(orders.`Fee`) |
|---------|-------------------|
| 123 | 13000 |
关于mysql - 在 JOIN 表上应用 DISTINCT 不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35229868/