我有两个表 blog 和 tbl_users。博客包含列“blogid”、“消息”、“标题”、“名称”、“创建”和“image_ctgy”。 tbl_users 包含列“userPic”、“image_ctgy”、“userId”。下面的代码显示博客消息以及基于相同 image_ctgy 的与该博客消息相关的图像。然而，我对 php 的了解有限，我在显示标题、名称和创建的列以及博客消息时遇到困难。任何帮助将不胜感激。
$sql = "SELECT blog.message as blogmessage, tbl_users.userPic as tblPics
FROM blog
LEFT JOIN tbl_users ON(blog.image_ctgy = tbl_users.image_ctgy)
ORDER by blog.blogid DESC";
$stmt = $db->prepare($sql);
$stmt->execute();
$blogs = array();
while (($row = $stmt->fetch(PDO::FETCH_ASSOC)))
{
$blogmessage = $row['blogmessage'];
$blogs[$blogmessage] [] = $row['tblPics'];
}
?>
<html>
<body>
<?php
foreach ($blogs as $blogmessage => $tblPics)
{
?>
<h2><?php echo $blogmessage; ?></h2>
<ul>
<?php
foreach ($tblPics as $tblPic)
{
?>
<li> <img src="cms3/user_images/<?php echo $tblPic; ?>"width="50px" height="50px"/></li>
<?php
}
?>
</ul>
<?php
}
?>
</body>
</html>
最佳答案
您可以使用此代码来获取与消息和用户图片一起创建的字段标题、名称:
<?php
$sql = "SELECT blog.message as blogmessage, blog.title, blog.name, blog.created, tbl_users.userPic as tblPics
FROM blog
LEFT JOIN tbl_users ON(blog.image_ctgy = tbl_users.image_ctgy)
ORDER by blog.blogid DESC";
$stmt = $db->prepare($sql);
$stmt->execute();
$blogs = array();
while (($row = $stmt->fetch(PDO::FETCH_ASSOC)))
{
// here you can get along with blogmessage another desired columns:
// title, name, created
$blogmessage = $row['blogmessage'];
$blogs[$blogmessage] [] = $row['tblPics'];
}
?>
<html>
<body>
<?php
foreach ($blogs as $blogmessage => $tblPics)
{
?>
<h2><?php echo $blogmessage; ?></h2>
<ul>
<?php
foreach ($tblPics as $tblPic)
{
?>
<li> <img src="cms3/user_images/<?php echo $tblPic; ?>"width="50px" height="50px"/></li>
<?php
}
?>
</ul>
<?php
}
?>
</body>
</html>
关于Php sql 左连接表回显表 1 中的列，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/35833480/