我正在尝试使用另一个表更新一个表。我无法确定如何在此处使用 LIKE %...% 功能。请帮帮我。
表1:
待更新表格:
id | location | value
------------
1 | california | I am going to be here soon.
2 | Nill | Hello I love playing chess and yes.
3 | Nill | my hotel room is just shitty!
4 | Nill | Why on earth God doesn’t live on earth!
5 | Nill | friends of friends and their dogs.
表2:
表格到检查来源:
uniqueid | location | keyword
---------------------
1 | Texas | Why on earth
2 | NewYork | friends and their
3 | Washington | love playing chess
4 | NewYork | their dogs
结果应该是:
id | location | value
------------
1 | California | I am going to be here soon.
2 | Washington | Hello I love playing chess and yes.
3 | Nill | my hotel room is just shitty!
4 | Texas | Why on earth God doesn’t live on earth!
5 |NewYork| friends of friends and their dogs.
——
我正在使用这个公式，但它给了我持续的错误:
UPDATE TableToBeUpdated, TableToCheckFrom
SET TableToBeUpdated.location = TableToCheckFrom.Location
WHERE TableToBeUpdated.Value LIKE %TableToCheckFrom.Keyword%
提前致谢!
最佳答案
您需要将 % 放在引号中并将它们连接到关键字。您需要连接两个表，以便可以引用两个表中的列。
UPDATE TableToBeUpdated AS u
JOIN TableToCheckFrom AS c ON u.Value LIKE CONCAT('%', c.Keyword, '%')
SET u.location = c.Location
关于mysql - Mysql 查询中出现 LIKE %...% 错误，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/36808590/