抱歉,标题令人困惑,不知道如何表达。
我有一个赛事表以及对这些赛事的投注表。我已经获取了每项赛事的总投注额,但我还想获取赔率(又名,一支球队的总投注额除以另一支球队的总投注额的商)。下注的参与者存储在 data_bets
表的 horse
列中。
例如,我想添加如下内容:
SELECT
SUM(data_bets.amount) WHERE data_bets.horse = data_events.challenger
/
SUM(data_bets.amount) WHERE data_bets.horse = data_events.contestant
AS bet_odds
下面是我现有的查询:
SELECT *,
SUM(data_bets.amount) AS total_pot,
COUNT(data_bets.member) AS total_bets,
COUNT(data_votes.member) AS total_votes,
data_platforms.name AS platform_name, data_platforms.icon AS platform_icon
FROM data_events
LEFT JOIN data_bets ON data_bets.event=data_events.id
LEFT JOIN data_votes ON data_votes.content_type=2 AND data_votes.content_id=data_events.id
LEFT JOIN data_platforms ON data_platforms.id=data_events.platform
WHERE status=1
GROUP BY data_events.id
ORDER BY total_pot DESC
这可以通过一个查询来完成吗?如果可能的话,我更愿意同时获取 challenger_odds
和 contestant_odds
,如下所示:
SELECT
SUM(data_bets.amount) WHERE data_bets.horse = data_events.challenger
/
SUM(data_bets.amount) WHERE data_bets.horse = data_events.contestant
AS challenger_odds,
SUM(data_bets.amount) WHERE data_bets.horse = data_events.contestant
/
SUM(data_bets.amount) WHERE data_bets.horse = data_events.challenger
AS contestant_odds
最佳答案
使用条件聚合:
SELECT (SUM(CASE WHEN data_bets.horse = data_events.challenger THEN data_bets.amount ELSE 0 END) /
SUM(CASE WHEN data_bets.horse = data_events.contestant THEN data_bets.amount END)
) as bet_odds
关于php - 检索两个 SUM(col) JOIN ON 不同值的商,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37647666/