php - 只是在 mysql 错误中插入空白数组()

Question

我只想将图像名称存储在 mysql 表中，但问题是它上传空白数组并给出错误

array to string conversion.

if(isset($_POST['prd_submit']) && isset($_FILES['prd_image'])){
// Define Input Variables
    $name = user_input($_POST['prd_name']);
    $detail =  user_input($_POST['prd_detail']);
    $image = $_FILES['prd_image'];
    $buy_link = user_input($_POST['prd_link']);
    $price = user_input($_POST['prd_price']);
    $category = $_POST['prd_category'];
    $country = $_POST['prd_country'];
    // Control Error Inputs
    if(empty($name)){
        $name_err = "Name is missing";
    }
    if(empty($detail)){
        $detail_err = "Detail is missing";
    }
    if(empty($price)){
        $price_err = "Price is missing";
    }
    if(empty($buy_link)){
        $buy_link_err = "Link is missing";
    }
    // File Upload Function
    $OutFiles = array();
    foreach($image as $Index=>$Items){
        foreach($Items as $Key=>$Item){
            $OutFiles[$Key][$Index] = $Item;
        }
    }
    if($OutFiles[0]['error']){
        $image_err = $Errors[$OutFiles[0]['error']];
    }else{
        foreach($OutFiles as $Index=>$File){
            $UploadDir = $DocRoot.'/upload/';
            $imageName = $File['name'];
            //GETTING FILE EXTENTION
            $file_ext = explode('.',$imageName);
            $file_ext = $file_ext[count($file_ext)-1];
            //FILE NAME
            $filename = (rand()).'-'.(time()).'.'.$file_ext;
            //FILE EXTENTION ERROR
            if($file_ext != "jpg" && $file_ext != "png" && $file_ext != "jpeg" && $file_ext != "gif"){
                $error = "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
            }elseif(move_uploaded_file($File['tmp_name'],$UploadDir.$filename)){
                $OutFiles[$Index]['name'] = $filename;
                $uploadok++;
            }elseif($uploadok == 0){
                $error = "Sorry File is Not Upload";
            }else{
                $uploadok--;
                $error = "Sorry File is Not Upload";
            }
        }
    }
    // Insert DB
    if($name_err == '' && $detail_err == '' && $image_err == '' && $price_err == '' && $buy_link_err == ''){            
        $Code = 0;
        try{
            $insert_data = ("INSERT INTO product (name,country,detail,image,price,buy_link,category,date_posted) VALUES ('$name','$country','$detail','$image','$price','$buy_link','$category','$date')");
            $insert_data = $conn->query($insert_data);
        }catch(PDOException $E){            
            $Code = $E->getCode();
        }
        if($Code == 0){
            $error =  "<div class='alert alert-success'>Your Product Registration Request Has Submitted!</div>";
        }elseif($Code == 23000){
            $error =  "<div class='alert alert-info'>Duplicate Entry</div>";
        }else{
            $error = "Unabel to enter data";
        }
    }

太令人困惑了，我在其中做错了什么，如果数组内爆，但我如何内爆，我只需要名称。

Answer 1

在 INSERT 查询中将 $image 更改为 $filename。

因为，$image = $_FILES['prd_image'];是一个数组，您想要存储刚刚上传到upload文件夹的文件名。因此，请使用使用 elseif(move_uploaded_file($File['tmp_name'],$UploadDir.$filename)){

上传的 $filename

查询

$insert_data = "INSERT INTO product (name,country,detail,image,price,buy_link,category,date_posted) VALUES ('$name','$country','$detail','$filename','$price','$buy_link','$category','$date')";

上传多个文件:将您的INSERT查询移至foreach内。每次成功上传时，它都会插入到表中。

foreach ($OutFiles as $Index => $File) {
  $UploadDir = $DocRoot . '/upload/';
  $imageName = $File['name'];
  //GETTING FILE EXTENTION
  $file_ext = explode('.', $imageName);
  $file_ext = $file_ext[count($file_ext) - 1];
  //FILE NAME
  $filename = (rand()) . '-' . (time()) . '.' . $file_ext;
  //FILE EXTENTION ERROR
  if ($file_ext != "jpg" && $file_ext != "png" && $file_ext != "jpeg" && $file_ext != "gif") {
    $error = "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
  } elseif (move_uploaded_file($File['tmp_name'], $UploadDir . $filename)) {
    $OutFiles[$Index]['name'] = $filename;
    $insert_data = "INSERT INTO product (name,country,detail,image,price,buy_link,category,date_posted) VALUES ('$name','$country','$detail','$filename','$price','$buy_link','$category','$date')";
    $insert_data = $conn->query($insert_data);
    $uploadok++;
  } elseif ($uploadok == 0) {
    $error = "Sorry File is Not Upload";
  } else {
    $uploadok--;
    $error = "Sorry File is Not Upload";
  }
}

并且，从下面删除 try/catch，因为现在每次上传都会插入。