php - mysql，1 个具有 where 条件的表与另一个具有不同 where 条件的表连接

Question

首先，我对标题中的粗俗术语表示歉意。

<? if ($thisguy == "noob") { echo("bear with me"); } ?>

我有两个表:

一个“评级”(行:产品、用户、评级、已添加) WHERE user = $thisuser[id],

和一个“产品”(id、名称)，其中 product.id = rating.product。

我广泛阅读了有关连接(内连接、外连接、左连接、右连接...)的内容，但我对此很困惑。

我需要数组中 Product.id = ratings.product 和 user = $thisuser[id] 的所有信息。

我正在使用这个:

$result = mysql_query("SELECT ratings.product, ratings.user, ratings.rating, ratings.added FROM ratings INNER JOIN products ON products.id = ratings.product AND user = $THISUSER[id]");
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    $product = $row['product'];
    $user = $row['user'];
    $rating = $row['rating'];
    $added = $row['added'];
    $pid = $row['id'];
    $pname = $row['name'];
    }
print("$user, $rating, $added, $THISUSER[id], $pname, $pid"); }

这会产生评级表中的所有内容(但只有一个实例)，而不会产生产品表中的任何内容...我已经尝试了 100 种不同的方法，但均无济于事。任何帮助将不胜感激!对我轻松一些。 *畏缩

Answer 1

您没有从产品表中选择任何列，请更改您的选择

$result = mysql_query("SELECT ratings.product, ratings.user, ratings.rating, ratings.added, products.id, products.name FROM ratings INNER JOIN products ON products.id = ratings.product where ratings.user = $THISUSER[id]");
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    $product = $row['product'];
    $user = $row['user'];
    $rating = $row['rating'];
    $added = $row['added'];
    $pid = $row['id'];
    $pname = $row['name'];
    }
print("$user, $rating, $added, $THISUSER[id], $pname, $pid"); }