如何获取带有分组日期的数据价格?
SELECT store.date, store.pic, owner.name,
SUM (CASE WHEN [>>GROUPED store.date<<] THEN store.price) AS total_price
FROM store
JOIN owner
ON store.pic = owner.name GROUP BY store.date
我想像这样显示:
+-------------+------+------------+
| date | name | price |
+-------------+------+------------+
| 2016-09-30 | John | 100000.00 |
| 2016-09-29 | Rey | 125000.00 |
+-------------+------+------------+
最佳答案
试试这个可能会对你有帮助,
SELECT store.date, store.pic, owner.name,SUM(store.price) AS total_price
FROM store
JOIN OWNER ON store.pic = owner.name
GROUP BY store.date
我不明白为什么你在查询中使用 case 语句
关于php - MySQL SUM 与分组日期,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39786362/