我想检索 mysql 结果,但我的查询不起作用,因为我是计算机编程或计算机数据库的新手。
SELECT guid, post_name
FROM `wp_posts`
WHERE `post_parent` = 0 and `post_type` = 'post' and post_title != 'Auto Draft'
返回:
guid post_name
http://localhost/?p=21 post-2-title
http://localhost/?p=12 post-4-title
还有
SELECT guid as children_url, post_parent as post_parent
FROM `wp_posts`
WHERE `post_parent` != 0 and `post_type` = 'attachment' and post_title != 'Auto Draft'
返回:
children_url post_parent
http://localhost/attachment-post-1 12
http://localhost/attachment-post-2 12
http://localhost/attachment-post-3 12
http://localhost/attachment-post-4 12
http://localhost/attachment-post-5 12
http://localhost/attachment-post-6 12
http://localhost/attachment-post-7 12
http://localhost/attachment-post-8 12
http://localhost/attachment-post-9 21
http://localhost/attachment-post-10 21
http://localhost/attachment-post-11 21
http://localhost/attachment-post-12 21
http://localhost/attachment-post-13 21
http://localhost/attachment-post-14 21
http://localhost/attachment-post-15 21
http://localhost/attachment-post-16 21
我尝试了多次查询但没有成功,
SELECT guid as children_url, post_parent as post_parent
FROM `wp_posts`
WHERE `post_parent` != 0 and `post_type` = 'attachment' and post_title != 'Auto Draft'
and SELECT guid, post_name FROM `wp_posts`
WHERE `post_parent` = 0 and `post_type` = 'post' and post_title != 'Auto Draft'
引发错误:
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT guid, post_name FROM
wp_posts
WHEREpost_parent
= 0 andpost_type
=' at line 1
我想要的结果是这样的:
children_url post_parent post_paraent_guid post_parent_title
http://localhost/attachment-post-1 12 http://localhost/?p=12 post-2-title
http://localhost/attachment-post-2 12 http://localhost/?p=12 post-2-title
http://localhost/attachment-post-3 12 http://localhost/?p=12 post-2-title
http://localhost/attachment-post-4 12 http://localhost/?p=12 post-2-title
http://localhost/attachment-post-5 12 http://localhost/?p=12 post-2-title
http://localhost/attachment-post-6 12 http://localhost/?p=12 post-2-title
http://localhost/attachment-post-7 12 http://localhost/?p=12 post-2-title
http://localhost/attachment-post-8 12 http://localhost/?p=12 post-2-title
http://localhost/attachment-post-9 21 http://localhost/?p=21 post-4-title
http://localhost/attachment-post-10 21 http://localhost/?p=21 post-4-title
http://localhost/attachment-post-11 21 http://localhost/?p=21 post-4-title
http://localhost/attachment-post-12 21 http://localhost/?p=21 post-4-title
http://localhost/attachment-post-13 21 http://localhost/?p=21 post-4-title
http://localhost/attachment-post-14 21 http://localhost/?p=21 post-4-title
http://localhost/attachment-post-15 21 http://localhost/?p=21 post-4-title
http://localhost/attachment-post-16 21 http://localhost/?p=21 post-4-title
如有任何帮助,我们将不胜感激。
谢谢
最佳答案
试试这个
SELECT
pc.guid as children_url,
pc.post_parent as post_parent,
pp.guid as post_paraent_guid,
pp.post_title as post_parent_title
FROM
wp_posts pc
left join wp_posts pp on pp.ID=pc.post_parent
WHERE
pc.post_type = 'attachment'
and pc.post_title != 'Auto Draft'
ORDER BY
pc.guid
关于mysql - 加入或连接mysql时出现语法错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39868022/