下面是我的查询,我想按描述(即字段 ld.descrip)对该查询进行排序。在下面的查询中哪里使用 order by 根据描述对数据进行排序。
Select ld.fact_code as costFactorID,ld.fact_code + ' ' + ld.descrip +' ' +'(' + convert(varchar,cast(ld.factor as money),1)+ '/' + ld.unit + ')' as costFactor, ap.alpha_code, ap.code, ld.neighborhd,ap.code
from lndfact ld
inner join app_lookup ap on ap.code like ld.neighborhd
inner join parcel p on p.neighborhd = ap.alpha_code
inner join assessments assmt on assmt.parcel_no = p.parcel_no
where assmt.assesmt_no = @0 and ld.value_type = @1
union All
Select ld.fact_code as costFactorID,ld.fact_code + ' ' + ld.descrip +' ' +'(' + convert(varchar,cast(ld.factor as money),1)+ '/' + ld.unit + ')' as costFactor, ap.alpha_code, ap.code, ld.neighborhd,ap.code
from lndfact ld
inner join app_lookup ap on ap.code like ld.neighborhd and ap.code = 77
最佳答案
仅在第一次查询时在统一查询别名末尾排序,(对应类型列的数量相同)
Select
ld.fact_code as costFactorID
,ld.fact_code + ' ' + ld.descrip +' ' +'(' + convert(varchar,cast(ld.factor as money),1)+ '/' + ld.unit + ')' as costFactor
, ap.alpha_code
, ap.code
, ld.neighborhd
,ap.code
from lndfact ld
inner join app_lookup ap on ap.code like ld.neighborhd
inner join parcel p on p.neighborhd = ap.alpha_code
inner join assessments assmt on assmt.parcel_no = p.parcel_no
where assmt.assesmt_no = @0 and ld.value_type = @1
union All
Select
ld.fact_code
,ld.fact_code + ' ' + ld.descrip +' ' +'(' + convert(varchar,cast(ld.factor as money),1)+ '/' + ld.unit + ')'
, ap.alpha_code
, ap.code
, ld.neighborhd
,ap.code
from lndfact ld
inner join app_lookup ap on ap.code like ld.neighborhd and ap.code = 77
ORDER BY alpha_code, code /* eg: */
关于mysql - sql中查询结果如何排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40817172/