我收到一条错误消息:
Parse error: syntax error, unexpected $end in /home/Jones/public_html/Assignment4/listCar.php on line 38
但是,第 38 行没有任何内容..谢谢
$sql = "SELECT * FROM CARS";
//Get the result set
$result = mysql_query($sql);
//Show the result using while statement and a html table tag
?>
<table border =1>
<tr>
<td> ID </td>
<td> Make </td>
<td> Model </td>
<td> Year </td>
<td> Mileage </td>
<td> First Name </td>
<td> Last Name </td>
<td> Email </td>
</tr>
<?php
while($row = mysql_fetch_array($result)){
echo $row ['ID'];
echo $row['MAKE'];
echo $row['MODEL'];
echo $row[YEAR];
echo $row[MILE];
echo $row['FNAME'];
echo $row['LNAME'];
echo $row['EMAIL'];
?>
}
</html>
最佳答案
<?php
while($row = mysql_fetch_array($result)){
echo $row ['ID'];
echo $row['MAKE'];
echo $row['MODEL'];
echo $row[YEAR];
echo $row[MILE];
echo $row['FNAME'];
echo $row['LNAME'];
echo $row['EMAIL'];
?>
}
改成这个
<?php
while($row = mysql_fetch_array($result)){
echo $row ['ID'];
echo $row['MAKE'];
echo $row['MODEL'];
echo $row[YEAR];
echo $row[MILE];
echo $row['FNAME'];
echo $row['LNAME'];
echo $row['EMAIL'];
}
?>
您已将 }
括号放在 ?>
之后,这会导致意外错误。
关于php - 解析错误: Help me solve my php error,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40966937/