假设我们有四个表,结构如下(表名 - 字段):
person - id, name
doctor - id_person, specialty
pacient - id_person, disease
appointment - doctor_id, pacient_id, date
如何构造一个查询来返回医生的姓名和专业、患者的姓名和疾病以及预约日期?
这是我到目前为止所得到的:
SELECT person.name, doctor.specialty, pacient.disease, appointment.date
FROM appointment
INNER JOIN person
ON appointment.pacient_id=person.id
INNER JOIN doctor
ON appointment.doctor_id=doctor.id_person
INNER JOIN pacient
ON appointment.pacient_id=pacient.id_person
但这并没有返回正确的字段。我认为问题在于为同一行中的两个不同 id(doctor 和 pacient)返回相同的字段(person.name
)。
最佳答案
您需要对 person
表进行两次单独的联接,并使用别名来标识各个表,如下所示:
select
dp.name as DoctorName
, doctor.specialty
, pp.name as PacientName
, pacient.disease
, appointment.date
from appointment
inner join doctor
on appointment.doctor_id = doctor.id_person
inner join person dp
on appointment.doctor_id = dp.id
inner join pacient
on appointment.pacient_id = pacient.id_person
inner join person pp
on appointment.pacient_id = pp.id
关于mysql - 用父子关系连接三个表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42888058/