我是 Spring MVC 的新手,我遇到了这个问题,我想获取 form:input 路径的值并将其传递给我的 Controller 。
Employee.java
public class Employee implements Serializable {
private static final long serialVersionUID = -3465813074586302847L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private int empId;
@Column
private String name;
@Column
private String email;
@Column
private String address;
@Column
private String telephone;
@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name="empUserId")
private EmployeeUserAccount employeeUserAccount;
//setters and getters
EmployeeUserAccount.java
public class EmployeeUserAccount implements Serializable {
private static final long serialVersionUID = -3465813074586302847L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private int empUserId;
@Column
private String userName;
@Column
private String password;
@Column
private String userLevel;
@OneToOne(mappedBy="employeeUserAccount")
private Employee employee;
EmployeeForm.jsp
<form:form action="saveEmployee" method="post" >
<table>
<form:hidden path="empId"/>
<input type="hidden" name="empUserId" value="${employee.employeeUserAccount.empUserId}"/>
<tr>
<td>Name:</td>
<td><form:input path="name" value="${employee.name}"/></td>
</tr>
<tr>
<td>Email:</td>
<td><form:input path="email" value="${employee.email}"/></td>
</tr>
<tr>
<td>Address:</td>
<td><form:input path="address" value="${employee.address}"/></td>
</tr>
<tr>
<td>Telephone:</td>
<td><form:input path="telephone" value="${employee.telephone}"/></td>
</tr>
<tr>
<td>Username:</td>
<td><form:input path="employeeUserAccount.userName" value="${employee.employeeUserAccount.userName}"/></td>
</tr>
<tr>
<td>Password:</td>
<td><form:input path="employeeUserAccount.password" value="${employee.employeeUserAccount.password}"/></td>
</tr>
<tr>
<td>Role:</td>
<td>
<%-- <form:select path="employeeUserAccount.userLevel">
<form:options />
</form:select> --%>
<form:select path="employeeUserAccount.userLevel">
<c:forEach items="${role}" var="r">
<c:choose>
<c:when test="${r==employee.employeeUserAccount.userLevel}">
<option value="${r}" selected="true">${r}</option>
</c:when>
<c:otherwise>
<option value="${r}">${r}</option>
</c:otherwise>
</c:choose>
</c:forEach>
</form:select>
</td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit" value="Save"></td>
</tr>
</table>
</form:form>
EmployeeController.java
@RequestMapping(value = "/saveEmployee", method = RequestMethod.POST)
public ModelAndView saveEmployee(@ModelAttribute("command") Employee employee, @RequestParam("empUserId") Integer empUserId) {
// How to get the employeeUserAccount.userName from path
// How to get the employeeUserAccount.password from path
最佳答案
一些要点:
1. 您的 DTO (Employee.java
) 应包含默认构造函数。
2. 更改以下代码:
<form:form action="saveEmployee" method="post" >
至:
<form:form action="saveEmployee" method="post" commandName="saveRecord">
3.将所有输入字段更改为-exp:
<form:input path="name" value="${employee.name}"/>
至
<form:input path="name" value="${name}"/>
我的意思是将“employee.fieldName
”更改为“fieldName
”
4.现在根据表单参数更改 Controller 的方法:
public ModelAndView saveEmployee(@ModelAttribute("saveRecord") Employee employee, @RequestParam("empUserId") Integer empUserId) {
//do anything you want
}
关于java - SPRING MVC - 如何获取表单:input path from JSP to Controller的值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44820798/