php - 在wamp上使用php从mysql数据库中随机选择

标签 php mysql sql wamp local

我正在尝试制作一种反击破案的开案。我的问题是,我怀疑原因是 wamp,它无法加载,或者需要很长时间,以至于我无法得到任何结果。我阅读了所有关于使用 mysqli 从数据库中选择随机项目的文章,它确实很慢并且不适合使用,但我不认为它会这么慢。所以我真的想知道这是否真的是导致问题的原因,或者是否存在我遗漏的完全不同的错误。预先感谢:)

if(isset($_GET['iid'])) {

    $iid = rString($_GET['iid']);

    $checkOwnerQuery = $data->query('SELECT * FROM inventory WHERE id = "'.$iid.'" AND ownerId = "'.$id.'"');
    $checkOwner = $checkOwnerQuery->num_rows;
    if ($checkOwner == 1) {
        // OWNER CONFIRMED, CONTINUE OPENING
        $randomNmbr = mt_rand(1, 100);
        if($randomNmbr == 1) {
            while($row = $data->query('SELECT * FROM caserewards WHERE chance = "1" ORDER BY RAND() LIMIT 1')->fetch_assoc()) {

                $rewardId = $row['id'];
                $rewardName = $row['name'];
                $rewardLore = $row['lore'];
                $rewardType = $row['type'];
                $rewardAmount = $row['amount'];
                $rewardChance = $row['chance'];
                $rewardColor = $row['color'];
                $rewardImg = $row['img'];
                $rewardActive = $row['active'];

            }
            echo $rewardName;

        } else if($randomNmbr >= 97) {

            while($row = $data->query('SELECT * FROM caserewards WHERE chance = "97" ORDER BY RAND() LIMIT 1')->fetch_assoc()) {

                $rewardId = $row['id'];
                $rewardName = $row['name'];
                $rewardLore = $row['lore'];
                $rewardType = $row['type'];
                $rewardAmount = $row['amount'];
                $rewardChance = $row['chance'];
                $rewardColor = $row['color'];
                $rewardImg = $row['img'];
                $rewardActive = $row['active'];

            }
            echo $rewardName;

        } else if($randomNmbr >= 95) {

            while($row = $data->query('SELECT * FROM caserewards WHERE chance = "95" ORDER BY RAND() LIMIT 1')->fetch_assoc()) {

                $rewardId = $row['id'];
                $rewardName = $row['name'];
                $rewardLore = $row['lore'];
                $rewardType = $row['type'];
                $rewardAmount = $row['amount'];
                $rewardChance = $row['chance'];
                $rewardColor = $row['color'];
                $rewardImg = $row['img'];
                $rewardActive = $row['active'];
            }
            echo $rewardName;

        } else if($randomNmbr >= 90) {

            while($row = $data->query('SELECT * FROM caserewards WHERE chance = "90" ORDER BY RAND() LIMIT 1')->fetch_assoc()) {

                $rewardId = $row['id'];
                $rewardName = $row['name'];
                $rewardLore = $row['lore'];
                $rewardType = $row['type'];
                $rewardAmount = $row['amount'];
                $rewardChance = $row['chance'];
                $rewardColor = $row['color'];
                $rewardImg = $row['img'];
                $rewardActive = $row['active'];
            }
            echo $rewardName;

        } else if($randomNmbr >= 80) {

            while($row = $data->query('SELECT * FROM caserewards WHERE chance = "80" ORDER BY RAND() LIMIT 1')->fetch_assoc()) {

                $rewardId = $row['id'];
                $rewardName = $row['name'];
                $rewardLore = $row['lore'];
                $rewardType = $row['type'];
                $rewardAmount = $row['amount'];
                $rewardChance = $row['chance'];
                $rewardColor = $row['color'];
                $rewardImg = $row['img'];
                $rewardActive = $row['active'];
            }
            echo $rewardName;

        } else if($randomNmbr >= 60) {

            while($row = $data->query('SELECT * FROM caserewards WHERE chance = "60" ORDER BY RAND() LIMIT 1')->fetch_assoc()) {

                $rewardId = $row['id'];
                $rewardName = $row['name'];
                $rewardLore = $row['lore'];
                $rewardType = $row['type'];
                $rewardAmount = $row['amount'];
                $rewardChance = $row['chance'];
                $rewardColor = $row['color'];
                $rewardImg = $row['img'];
                $rewardActive = $row['active'];
            }
            echo $rewardName;

        } else if($randomNmbr >= 50) {

            goto a;

        } else if($randomNmbr <= 50 && $randomNmbr != 1) {

a:

            while($row = $data->query('SELECT * FROM caserewards WHERE chance = "50" ORDER BY RAND() LIMIT 1')->fetch_assoc()) {

                $rewardId = $row['id'];
                $rewardName = $row['name'];
                $rewardLore = $row['lore'];
                $rewardType = $row['type'];
                $rewardAmount = $row['amount'];
                $rewardChance = $row['chance'];
                $rewardColor = $row['color'];
                $rewardImg = $row['img'];
                $rewardActive = $row['active'];
            }
            echo $rewardName;

        } else {
            echo 'Major danger';
        }
        echo '<div class="item_img_center" style="background-image: url()"></div>';

    } else {
        header('Location: inventory.php');
    }
} else {
    header('Location: inventory.php');
}

最佳答案

我认为您不希望在随机查询周围使用 while 循环,因为每次返回结果时都会重新运行查询(即永远,因为它们将始终返回除非 caserewards 完全为空,否则为结果)。

尝试仅使用:

$row = $data->query('SELECT * FROM caserewards WHERE chance = "50" ORDER BY RAND() LIMIT 1')->fetch_assoc();

$rewardId = $row['id'];
$rewardName = $row['name'];
$rewardLore = $row['lore'];
$rewardType = $row['type'];
$rewardAmount = $row['amount'];
$rewardChance = $row['chance'];
$rewardColor = $row['color'];
$rewardImg = $row['img'];
$rewardActive = $row['active'];

对所有其他查询进行类似的更新。

关于php - 在wamp上使用php从mysql数据库中随机选择,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45506633/

相关文章:

java - 无法在数据库中写入新条目

php - 覆盖 wordpress 登录重定向功能

MySQL - 在查询中更新 WHERE 字段,LIMIT 被拒绝

IDS 的 Java 应用程序设计

sql - 您可以在 Rails Active Record 中按计数选择唯一性吗?

mysql - 如何从每个数据集一行中的标准化表中检索值?

php - 如何检索每一行的 ID,然后将其分配给链接

PHP+MYsql新安全实践

mysql - DATE_ADD 在生产服务器上返回 NULL,在开发中工作

php - MySQL 循环或嵌套查询