php - 解析sql响应数组

Question

Sql 响应如下所示:名称|地点|日期|地址。行可以包含相同的名称、位置和日期，但地址每次都会更改。因此，我需要将此响应放入数组中，如下所示:

[0] => 'Name':'...',
       'Locality':'...',
       'Date':'...',
       'Address': [0] => '...',
                  [1] => '...',
                  [2] => '...',
                  ...
...

我尝试使用此代码，但不起作用=(

while($r = mysqli_fetch_assoc($q_res)){
    $i = 0;

    if(!in_array($r['watcher_name'], $daily_quests)){          
        $daily_quests[$i]['name'] = $r['name'];
        $daily_quests[$i]['date'] = $r['date'];
        $daily_quests[$i]['locality'] = $r['locality'];
    }
    else{
        $daily_quests['address'] = $intrnal_addr[$i => $r['address']];
    }

}

Answer 1

试试这个:

//Initialisation
$name = '';
$daily_quests = array();
$i = -1;

while($r = mysqli_fetch_assoc($q_res)){

    //If the row is different than precedent
    if (strcmp($r['name'], $name) != 0)
    {
        $i++;
        $name = $r['name'];
        $daily_quests[$i] = array();
        $daily_quests[$i]['name'] = $r['name'];
        $daily_quests[$i]['date'] = $r['date'];
        $daily_quests[$i]['locality'] = $r['locality'];
        $daily_quests[$i]['address'] = array(); 
    }
    // For each row, we must add address
    $daily_quests[$i]['address'][] = $r['address']
}

但是，我们假设该名称是唯一的。与 id 进行比较更安全。