具有多个组的 Mysql Rollup

Question

Mytable，其 ID 作为自动增量客户、日期和金额 我想做一个汇总，将每个客户每天的金额相加 我的意思是汇总按日期和客户分组 我的结果应该是这样的:

+---------+--------------+--------------+------------+
| Id      | Date         | Customer     |     Amount |  
+---------+--------------+--------------+------------+
| 1       | 2017-09-19   |          B   |        10  | 
| 4       | 2017-09-19   |          B   |        15  | 
| 8       | 2017-09-19   |          B   |        02  | 
| 6       | 2017-09-19   |          B   |        18  |
| 5       | 2017-09-19   |          B   |        05  | 
| Total   | NULL         |          B   |        50  | 

| 9       | 2017-09-19   |         C    |        11  | 
|14       | 2017-09-19   |         C    |        10  |
| 12      | 2017-09-19   |         C    |        09  | 
| Total   | NULL         |         C    |        30  | 

| 11       | 2017-09-18  |         B    |         20 | 
| 15       | 2017-09-18  |         B    |         40 |
| Total    | NULL        |         B    |         60 | 

| 10       | 2017-09-18  |         A    |         1  | 
| 13       | 2017-09-18  |         A    |         1  | 
| 16       | 2017-09-18  |         A    |         1  | 
| 7        | 2017-09-18  |         A    |         1  |
| 3        | 2017-09-18  |         A    |         1  | 
| Total    | NULL        |         A    |         5  | 

| 2        | 2017-09-18   |         C   |        90  | 
| Total    | NULL         |         C   |        90  | 

我尝试过:

Select
Mytable.Id,
Mytable. Date,
Mytable.Customer,
Mytable.Amount
From Mytable
GROUP BY Mytable. Date, Mytable.Customer WITH ROLLUP

但这并没有按预期工作。请帮忙

Answer 1

您需要一个聚合。这符合你的要求吗？

select t.Date, t.Customer,
       sum(t.Amount) as Amount
from Mytable t
group by t.Date, t.Customer with rollup;

如果您确实想要 id，那么:

select t.id, t.Date, t.Customer,
       sum(t.Amount) as Amount
from Mytable t
group by t.id, t.Date, t.Customer with rollup;