MySQL 查询在 Workbench 中有效，但 hibernate 抛出 MySQLSyntaxErrorException

Question

我有一个查询，它给我带来了 2 个结果。当我在 MySQL Workbench 上使用它时它工作正常，但是当我在 hibernate 映射上将它用作公式时，我收到此错误:

SEVERE: Servlet.service() for servlet [FacesServlet] in context with path [/glic_web_admin] threw exception [javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not extract ResultSet] with root cause com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'shipmentre0_.SEPARATOR ', ') FROM glic_shipment s LEFT OUTER JOIN glic_shipment' at line 1

这是我在 hibernate 映射中的 SQL 查询:

<property name="supplier" type="java.lang.String"
            formula="(SELECT GROUP_CONCAT(pnSon.supplier SEPARATOR ', ')
     FROM glic_shipment s 
     LEFT OUTER JOIN glic_shipment sSon ON sSon.id_shipment_parent = s.id
     LEFT OUTER JOIN glic_rel_purchase_shipment_common_data pscdSon ON pscdSon.id = sSon.id_common_data
     LEFT OUTER JOIN glic_purchase_notice pnSon ON pnSon.id = pscdSon.id_purchase_notice)" />   

此查询的预期输出是一个字符串，其中连接了结果。我知道这是一个语法问题，但我没有找到如何解决这个问题。

编辑: 这是 hibernate 正在执行的查询:

(SELECT GROUP_CONCAT(pnSon.supplier shipmentre0_.SEPARATOR ', ') FROM glic_shipment s  LEFT OUTER JOIN glic_shipment sSon ON sSon.id_shipment_parent = s.id LEFT OUTER JOIN glic_rel_purchase_shipment_common_data pscdSon ON pscdSon.id = sSon.id_common_data LEFT OUTER JOIN glic_purchase_notice pnSon ON pnSon.id = pscdSon.id_purchase_notice) as formula27_0_

我该如何解决这个问题？

Answer 1

你不必写SEPARATOR ', '尝试如下:

<property name="supplier" type="java.lang.String"
            formula="(SELECT GROUP_CONCAT(pnSon.supplier, ' ')
     FROM glic_shipment s 
     LEFT OUTER JOIN glic_shipment sSon ON sSon.id_shipment_parent = s.id
     LEFT OUTER JOIN glic_rel_purchase_shipment_common_data pscdSon ON pscdSon.id = sSon.id_common_data
     LEFT OUTER JOIN glic_purchase_notice pnSon ON pnSon.id = pscdSon.id_purchase_notice)" />