mysql select not 不起作用

Question

我只想选择没有产品 ID 为 11 的行的学生 ID。但我不能。我该怎么办？

BEGIN TRANSACTION;
CREATE TABLE STUDENTS(Id integer PRIMARY KEY, name text,year_born integer 
);

CREATE TABLE PROJECT(project_id integer,title text,project_owner 
text,year_written integer );

CREATE TABLE PROJECTWORKS(student_id integer,project_id integer);
INSERT INTO STUDENTS VALUES(1598,'james',1996);
INSERT INTO STUDENTS VALUES(2479,'andre',1996);
INSERT INTO STUDENTS VALUES(3682,'pierre',1997);


INSERT INTO PROJECT VALUES(10,'A','ABC',2008);
INSERT INTO PROJECT VALUES(11,'B','ABC',2010);
INSERT INTO PROJECT VALUES(12,'C','ABC',2016);
INSERT INTO PROJECT VALUES(13,'D','CBA',2014);


INSERT INTO PROJECTWORKS VALUES(1598,10);
INSERT INTO PROJECTWORKS VALUES(1598,11);
INSERT INTO PROJECTWORKS VALUES(1598,12);
INSERT INTO PROJECTWORKS VALUES(3682,12);
INSERT INTO PROJECTWORKS VALUES(3682,13);
INSERT INTO PROJECTWORKS VALUES(2479,12);

SELECT * FROM STUDENTS;
SELECT * FROM PROJECT;
SELECT * FROM PROJECTWORKS;

SELECT DISTINCT student_id FROM PROJECTWORKS
WHERE not project_id=11 and (project_id=10 OR project_id=12 OR 
project_id=13);

我只想要 3682 和 2479 因为 1598 有 11。

Answer 1

NOT EXISTS 非常适合这个:

SELECT DISTINCT student_id
FROM PROJECTWORKS p
WHERE project_id IN (10, 12, 13)
AND NOT EXISTS
(SELECT 1
 FROM PROJECTWORKS p2
 WHERE p.student_id = p2.student_id
 AND p2.project_id = 11);

此外，我假设您的意思是您不需要 ID 11，因为我在您的示例中没有看到 14。