我有一个约会表，需要在表中添加一个评论列，当用户在文本框中键入内容并单击提交时可以更新评论。我已经尝试了下面的代码，但无法理解为什么它不能正常运行。我对此做了很多研究，但遇到了一个又一个的障碍，所以我真的希望您能在这方面提供帮助，非常感谢!
这是我的代码:
<!-- <form method="post" action="delete.php" > -->
<form method="post" action="tea_appview.php">
<table cellpadding="0" cellspacing="0" border="0" class="table table-condensed" id="example">
<!-- <table cellpadding="0" cellspacing="0" border="0" class="table table-bordered" id="example"> -->
<thead>
<tr>
<th>appoinment ID</th>
<th>Date</th>
<th>time</th>
<th>subject</th>
<th>Appointment from [parent]</th>
<th>Appointment to (teacher) </th>
<th> accept/reject </th>
<th>state</th>
<th>comm</th>
</tr>
</thead>
<tbody>
<?php
$query=mysqli_query($conn, "select * from `app` left join `par` on par.par_id=app.par_id
left join `tea` on tea.tea_id=app.tea_id
ORDER BY app_id DESC");
if($query === false)
{
throw new Exception(mysqli_error($conn));
}
while($row=mysqli_fetch_array($query))
{
$ann_id=$row['app_id'];
$date=$row['date'];
$msg=$row['time'];
$username = $row['username'];
$username = $row['p_username'];
$sub = $row['sub'];
?>
<tr>
<td><?php echo $row['app_id'] ?></td>
<td> <?php echo date('j/m/y',strtotime($row['date'])); ?></td>
<td><?php echo $row['time'] ?></td>
<td><?php echo $row['sub'] ?></td>
<td><?php echo $row['p_username'] ?></td>
<td><?php echo $row['username'] ?></td>
<td>
<a href="tea_appview.php?app_id=<?php echo $row['app_id'] . "&" . "state=reject";?>" class="reject">reject</a>
<a href="tea_appview.php?app_id=<?php echo $row['app_id'] . "&" . "state=accept";?>" class="accept">accept</a>
</td>
<td><?php echo $row['state'] ?></td>
<td><input type="text" name="comm">
<input type="submit" name="submit" value="submit">
</td>
</tr>
<?php
//---------PROBLEM IS HERE-----------------------
//if(isset($_GET['app_id'], $_POST['submit'])!="")
if(isset($_GET['app_id']) && $_POST['submit'] !="")
{
$stmt = mysqli_prepare($conn, "UPDATE app SET comm = ? WHERE app_id = ?");
mysqli_stmt_bind_param($stmt, "sd", $_GET['comm'], $_GET['app_id']);
$stmt->execute();
$stmt->close();
}
//-------------------------------
if (isset($_GET['state'], $_GET['app_id']))
{
$stmt = mysqli_prepare($conn, "UPDATE app SET state = ? WHERE app_id = ?");
mysqli_stmt_bind_param($stmt, "sd", $_GET['state'], $_GET['app_id']);
$stmt->execute();
$stmt->close();
}
}
?>
</tbody>
</table>
</div>
</form>
最佳答案
问题出在您的表单标记中
<form method="post" action="file.php?app_id=VALUE&state=VALUE">
您必须使用处理代码所用的文件以及 $_GET 参数中的变量来填写您的操作。另请检查此
if(isset($_GET['app_id']) && $_POST['submit'] !="")
关于php - 如何在PHP中的表格行中添加注释，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/49103238/