php - Laravel 5.4 查询生成器存在 groupBy 问题

Question

我正在尝试将此查询转换为 Laravel 5.4 中的查询构建器:

SELECT
    oc.id,
    oc.name,
    oat.user_id,
    p.first_name,
    p.last_name
FROM
    oauth_clients oc
    LEFT JOIN oauth_access_tokens oat ON oc.id = oat.client_id
    JOIN users u on u.id = oat.user_id
    JOIN people p on p.id = u.person_id
WHERE oc.revoked = false AND oc.password_client = true
GROUP BY oc.id, oat.user_id

并收到此错误 barf: 传递给 Illuminate\Database\Connection::prepareBindings() 的参数 1 必须是给定的数组类型，字符串，在/var/www/html/source/luniverse/vendor 中调用/laravel/framework/src/Illuminate/Database/Connection.php 第 648 行并定义 这是我的尝试(众多尝试之一):

$tokens = DB::select('oc.id','oc.name','oat.user_id','p.first_name','p.last_name')
                ->from('oauth_clients as oc')
                ->leftJoin('oauth_access_tokens as oat', 'oc.id', '=', 'oat.client_id')
                ->join('users as u', 'u.id', '=', 'oat.user_id')
                ->join('people as p', 'p.id', '=', 'u.person_id')
                ->where('oc.revoked', '=', 'false')
                ->where('oc.password_client', '=', 'true')
                ->groupBy('oc.id')
                ->groupBy('oat.user_id')
                ->get();

数据库配置设置为严格模式，但这似乎并不能完全解释该特定错误。原始查询在数据库 GUI 中运行良好。

Answer 1

更改 groupby 代码，例如

$tokens = DB::select('oc.id','oc.name','oat.user_id','p.first_name','p.last_name')
            ->from('oauth_clients as oc')
            ->leftJoin('oauth_access_tokens as oat', 'oc.id', '=', 'oat.client_id')
            ->join('users as u', 'u.id', '=', 'oat.user_id')
            ->join('people as p', 'p.id', '=', 'u.person_id')
            ->where('oc.revoked', '=', 'false')
            ->where('oc.password_client', '=', 'true')
            ->groupBy('oc.id','oat.user_id')
            ->get();