我创建了一个注册表单,其中包含用户名、用户名、电子邮件和密码。我还使用 XAMPP 控制面板创建了一个 sql 数据库,将数据库命名为“registration”,并创建了一个名为“users”的表来存储所有输入。
当用户输入这些数据时,他们应该看到登录页面,并且在后台数据应该存储在数据库中。但是当我打开 phpmyadmin 来检查表时,没有保存任何数据。
下面是我用来将用户输入发送到数据库(即我的“server.php”文件)的代码:
<?php
session_start();
// initializing variables
$name = "";
$email = "";
$username = "";
$errors = array();
// connect to the database
$db = mysqli_connect('localhost', 'root', 'root', 'registration');
// REGISTER USER
if (isset($_POST['reg_user'])) {
// receive all input values from the form
$name = mysqli_real_escape_string($db, $_POST['name']);
$email = mysqli_real_escape_string($db, $_POST['email']);
$username = mysqli_real_escape_string($db, $_POST['username']);
$password_1 = mysqli_real_escape_string($db, $_POST['password_1']);
$password_2 = mysqli_real_escape_string($db, $_POST['password_2']);
// form validation: ensure that the form is correctly filled ...
// by adding (array_push()) corresponding error unto $errors array
if (empty($name)) { array_push($errors, "Name is required");
}
if (empty($email)) { array_push($errors, "Email is required");
}
if (empty($username)) { array_push($errors, "Username is required"); }
if (empty($password_1)) { array_push($errors, "Password is required"); }
if ($password_1 != $password_2) {
array_push($errors, "The two passwords do not match");
}
// first check the database to make sure
// a user does not already exist with the same username and/or email
$user_check_query = "SELECT * FROM users WHERE username='$username' OR email='$email' LIMIT 1";
$result = mysqli_query($db, $user_check_query);
$user = mysqli_fetch_assoc($result);
if ($user) { // if user exists
if ($user['username'] === $username) {
array_push($errors, "Username already exists");
}
if ($user['email'] === $email) {
array_push($errors, "email already exists");
}
}
// Finally, register user if there are no errors in the form
if (count($errors) == 0) {
$password = md5($password_1);//encrypt the password before saving in the database
$query = "INSERT INTO users (name, email, username, password)
VALUES('$name', '$email', '$username', '$password')";
mysqli_query($db, $query);
$_SESSION['username'] = $username;
$_SESSION['success'] = "You are now logged in";
header('location: login.php');
}
}
// ...
// ...
// LOGIN USER
if (isset($_POST['login_user'])) {
$username = mysqli_real_escape_string($db, $_POST['username']);
$password = mysqli_real_escape_string($db, $_POST['password']);
if (empty($username)) {
array_push($errors, "Username is required");
}
if (empty($password)) {
array_push($errors, "Password is required");
}
if (count($errors) == 0) {
$password = md5($password);
$query = "SELECT * FROM users WHERE username='$username' AND password='$password'";
$results = mysqli_query($db, $query);
if (mysqli_num_rows($results) == 1) {
$_SESSION['username'] = $username;
$_SESSION['success'] = "You are now logged in";
header('location: https://georginahughes48.wixsite.com/makeupyourmind');
}else {
array_push($errors, "Wrong username/password combination");
}
}
}
?>
如果需要任何进一步的代码来帮助我解决此问题,请告诉我。提前致谢!
最佳答案
在连接代码后添加此行
if($db->connect_errno)
{
echo "Error: ( " .$db->errorno. " )". $db->error;
die;
}
只需替换此代码
if (count($errors) == 0) {
$password = md5($password_1);//encrypt the password before saving in the database
$query = "INSERT INTO users (name, email, username, password)
VALUES('$name', '$email', '$username', '$password')";
if( mysqli_query($db, $query))
{
$_SESSION['username'] = $username;
$_SESSION['success'] = "You are now logged in";
header('location: login.php');
}
else
{
echo mysqli_error($db);
}
}
}
检查是否有错误。
关于php - SQL数据库不存储用户输入,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49958107/